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3 years ago

Is negitive 1.8 greater than negitive 2.1

Mathematics

2 answers:

leva [86]3 years ago

5 0

Answer:

(-1.8) is greater than (-2.1)

Step-by-step explanation:

This is because when finding greater or than less with negatives you use what farther or closer to zero(0) For example our situation right here (-1.8) and (-2.1), -1.8 is closer to zero than (-2.1). If you were trying to find is was what was less than, than you would look at whats farther from 0(zero).

Llana [10]3 years ago

3 0

Unlike positives, with negatives, the larger a number is, the smaller it is.

Example :
4 > 2

-4 < -2

so -1.8 is GREATER then -2.1

here is a tip :
picture ur number line....plot -2.1....any number to the right is greater and any number to the left is less...and since -1.8 is to the right of -2.1, it is greater then -2.1

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Sunscreen is priced at $10.00 per bottle, plus 8% tax. If Sonya purchases a bottle of sunscreen with a $20.00 bill, then what is

MatroZZZ [7]

Answer:

$9.20

Step-by-step explanation:

the tax would be $0.80 because 8% of $10 is $0.80

so the total cost is $10.80

now subtract that by her $20 bill

20-10.80= 9.20

so she will be given $9.20 back in change

hope this helps luv <3

5 0

3 years ago

Read 2 more answers

Find the equation of ellipse passing throgh (1,4) and (-3,2)

irinina [24]

Answer:

$\displaystyle \frac{ {3x}^{2} }{ 35 } + \frac{{2y}^{2} }{ 35 } = 1$

Step-by-step explanation:

we want to figure out the ellipse equation which passes through (1,4) and (-3,2)

the standard form of ellipse equation is given by:

$\displaystyle \frac{(x - h {)}^{2} }{ {a}^{2} } + \frac{(y - k {)}^{2} }{ {b}^{2} } = 1$

where:

(h,k) is the centre
a is the horizontal redius
b is the vertical radius

since the centre of the equation is not mentioned, we'd assume it (0,0) therefore our equation will be:

$\displaystyle \frac{ {x}^{2} }{ {a}^{2} } + \frac{{y}^{2} }{ {b}^{2} } = 1$

substituting the value of x and y from the point (1,4),we'd acquire:

$\displaystyle \frac{ 1}{ {a}^{2} } + \frac{16}{ {b}^{2} } = 1$

similarly using the point (-3,2), we'd obtain:

$\displaystyle \frac{ 9}{ {a}^{2} } + \frac{4 }{ {b}^{2} } = 1$

let 1/a² and 1/b² be q and p respectively and transform the equation:

$\displaystyle \begin{cases} q + 16p = 1 \\ 9q + 4p = 1 \end{cases}$

solving the system of linear equation will yield:

$\displaystyle \begin{cases} q = \dfrac{3}{35} \\ \\ p = \dfrac{2}{35} \end{cases}$

substitute back:

$\displaystyle \begin{cases} \dfrac{1}{ {a}^{2} } = \dfrac{3}{35} \\ \\ \dfrac{1}{ {b}^{2} } = \dfrac{2}{35} \end{cases}$

divide both equation by 1 which yields:

$\displaystyle \begin{cases} {a}^{2} = \dfrac{35}{ 3} \\ \\ {b}^{2} = \dfrac{35}{2} \end{cases}$

substitute the value of a² and b² in the ellipse equation , thus:

$\displaystyle \frac{ {x}^{2} }{ \dfrac{35}{3} } + \frac{{y}^{2} }{ \dfrac{35}{2} } = 1$

simplify complex fraction:

$\displaystyle \frac{ {3x}^{2} }{ 35 } + \frac{{2y}^{2} }{ 35 } = 1$

and we're done!

(refer the attachment as well)

8 0

3 years ago

In the 1980s an average mortgage rate was around 18.5 how much less per month would a 150000 30 year mortgage by today if the cu

lianna [129]

Answer:

$1516.69 per month less

Step-by-step explanation:

The formula for the monthly payment A on a loan of principal P, annual rate r, for t years is ...

A = P(r/12)/(1 -(1 +r/12)^(-12t))

For the 18.5% loan, the monthly payment is ...

A = 150000(.185/12)/(1 -(1 +.185/12)^(-12·30)) ≈ 2321.92

For the 5% loan, the monthly payment is ...

A = 150000(.05/12)/(1 -(1 +.05/12)^-360) ≈ 805.23

The mortgage at 5% would be $1516.69 less per month.

7 0

4 years ago

What is the HCF of 66, 121 ,132

gayaneshka [121]

11

66=11×6
121=11×11
132=11×12

5 0

4 years ago

Read 2 more answers

10 ,15 as a simple form

NikAS [45]

10,15 in the simplest form is 2,3

5 0

4 years ago