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adell [148]
3 years ago
7

Find the volume of the ellipsoid x^2+y^2+9z^2=64

Mathematics
1 answer:
yuradex [85]3 years ago
4 0
Parameterize the ellipsoid using the augmented spherical coordinates:

\begin{cases}x=\frac18\rho\cos\theta\sin\varphi\\\\y=\frac18\rho\sin\theta\sin\varphi\\\\z=\frac38\rho\cos\varphi\end{cases}

Then the Jacobian for the change of coordinates is

\mathbf J=\dfrac{\partial(x,y,z)}{\partial(\rho,\theta,\varphi)}=\begin{bmatrix}\frac18\cos\theta\sin\varphi&-\frac18\rho\sin\theta\sin\varphi&\frac18\rho\cos\theta\cos\varphi\\\\\frac18\sin\theta\sin\varphi&\frac18\rho\cos\theta\sin\varphi&\frac18\rho\sin\theta\cos\varphi\\\frac38\cos\varphi&0&-\frac38\rho\sin\varphi\end{bmatrix}

which has determinant

\det\mathbf J=-\dfrac3{512}\rho^2\sin\varphi

Then the volume of the ellipsoid is given by

\displaystyle\iiint_E\mathrm dx\,\mathrm dy\,\mathrm dz=\iiint_E|\det\mathbf J|\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi

where E denotes the spaced contained by the ellipsoid. In particular, we have the definite integral and volume

\displaystyle\frac3{512}\int_{\varphi=0}^{\varphi=\pi}\int_{\theta=0}^{\theta=2\pi}\int_{\rho=0}^{\rho=1}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=\dfrac\pi{128}
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Answer:

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b) -5x^{2}+3x+9

Step-by-step explanation:

a) Let the required polynomial be p(x).

We have the relation, 5x^{2}-3x-9 + p(x) = 18

i.e. p(x) = 18 -5x^{2}+3x+9

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b) Let the required polynomial be q(x).

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i.e. q(x) = 0 -5x^{2}+3x+9

i.e. q(x) = -5x^{2}+3x+9

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3 years ago
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HELPPP WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Zepler [3.9K]
I think it's 1/2 because 5/10= 1/2

I hope this helps!
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Step-by-step explanation:

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