Answer:
love jacobt tremblay
Step-by-step explanation:
Answer:
"A Type I error in the context of this problem is to conclude that the true mean wind speed at the site is higher than 15 mph when it actually is not higher than 15 mph."
Step-by-step explanation:
A Type I error happens when a true null hypothesis is rejected.
In this case, as the claim that want to be tested is that the average wind speed is significantly higher than 15 mph, the null hypothesis has to state the opposite: the average wind speed is equal or less than 15 mph.
Then, with this null hypothesis, the Type I error implies a rejection of the hypothesis that the average wind speed is equal or less than 15 mph. This is equivalent to say that there is evidence that the average speed is significantly higher than 15 mph.
"A Type I error in the context of this problem is to conclude that the true mean wind speed at the site is higher than 15 mph when it actually is not higher than 15 mph."
Answer:
900 g
Step-by-step explanation:
let e be extension and w be weight
given e varies directly as w then the equation relating them is
e = kw ← k is the constant of variation
to find k use the condition w = 150 , e = 2.9 , then
2.9 = 150k ( divide both sides by 150 )
= k , that is
k = 
e = w ← equation of variation
when e = 17.4 , then
17.4 = w ( multiply both sides by 1500 )
26100 = 29w ( divide both sides by 29 )
900 = w
Answer:
y = -28 ÷ x
Step-by-step explanation:
The standard format of a inversely proportional equation goes by the format of y = k ÷ x. The question asks us to write an equation if y = 7 when x = -4 and y varies inversely with x.
So we substitute the values y = 7 and x = -4 in the equation y = k ÷ x
K = constant, we have to work this out
7 = k ÷ -4
7 × - 4 = k
k = - 4 × 7
k = -28
k = -28 So then we put this back into the original y = k ÷ x to find our final equation which is y = -28 ÷ x
AGB and DGE are acute angles so DGE= 30°. EGF is 100° (50+30+100 {in that order}) (idk the rest
