Answer: -133
Step-by-step explanation:
1. 4(-6^2+3)-2(1/2)
v
2. 4(-36+3)-2(1/2)
v
3. 4(-33)-2(1/2)
v v
4. -132-1
v
5. -133
How many 5-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, if repetitions of digits are allowed?
valentinak56 [21]
50 different 5-digit numbers because it would be 5x10 which equals 50.
Answer:
6J = 72
Step-by-step explanation:
Because it says the product, it is talking about multiplication.
J would be Jamelle's age
6 is the excess number given.
72 is the answer
thus it would be 6*J or 6J = 72
They mowed total of 11/15 (5/15 + 2/5) already, so they still have 4/15.
