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AlladinOne [14]
2 years ago
9

What is (6 + 3e)4 - 5e and 3(x - 5) + 7(x + 2) ?

Mathematics
1 answer:
Dafna11 [192]2 years ago
6 0

idk lol use photomath

You might be interested in
1.what is a sports car average acceleration if it can go from 0m/s to 27m/s in 6.0 seconds?
Flauer [41]

Answer:

1.4.5m/s^2

2.6.25m/s^2

3.15m/s^2

4.0.05m/s^2

Step-by-step explanation:

a=v-u

----

t

27-0

------ = 27/6

6

=4.5m/s^2

u=4.5m/s

v=24.5m/s

t=3.2s

(24.5-4.5)÷3.2

=20/3.2

=6.25m/s^2

v=80m/s

u=50m/s

t=2s

(80-50)÷2

15m/s^2

v=0.80m/s

u=0.50m/s

t=6s

(0.80-0.50)÷6

=0.05m/s^2

5 0
2 years ago
If y = 9 inches, z = 14 inches, h = 5 inches, and w = 4 inches, what is the area of the object?
vekshin1

Answer:

126

Step-by-step explanation:

7 0
1 year ago
What is 3/4 plus 4 1/3
OlgaM077 [116]

Answer:

Step-by-step explanation:

You need to change the denominator into a the least common denominator, 4 and 3 both have 12 in common. 12 is your new denominator but what you to the bottom you must do to the top. So when you multiply 3/4 by 3/3 you will get 9/12.

Then you want to make 4 1/3 into a improper fraction, which would be 13/3 you want to multiply this by 4 and you will get 52/12. You will then add 52/12 to 9/12 and get 61/12 or 5 1/12.

If you need any more help please let me know.

4 0
3 years ago
How to show these 2 problems are inverses
nataly862011 [7]
\bf \begin{cases}
f(x)=\sqrt[3]{7x-2}\\\\
g(x)=\cfrac{x^3+2}{7}
\end{cases}\\\\
-----------------------------\\\\
now
\\\\
f[\ g(x)\ ]\implies f\left[ \frac{x^3+2}{7} \right]\implies \sqrt[3]{7\left[ \frac{x^3+2}{7} \right]-2}\implies \sqrt[3]{x^3+2-2}
\\\\\\
\sqrt[3]{x^3}\implies x\\\\
-----------------------------\\\\
or
\\\\
g[\ f(x)\ ]\implies g\left[\sqrt[3]{7x-2}\right]\implies \cfrac{\left[\sqrt[3]{7x-2}\right]^3+2}{7}
\\\\\\
\cfrac{7x-2+2}{7}\implies \cfrac{7x}{7}\implies x

thus f[ g(x) ] = x indeed, or g[ f(x) ] =x, thus they're indeed inverse of each other
8 0
2 years ago
Solve for a.<br>g= 1+2a<br> -------<br> a
vladimir2022 [97]
Subtract g add 1 divide by 2a
8 0
3 years ago
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