The factors illustrate they the sides of the rectangles are:
- (x - 1)(x - 2)
- (2x - 3)(x + 2)
<h3>How to get the factors?</h3>
The first equation given is x² - 3x + 2.
= x² - 3x + 2.
= x² - x - 2x + 2
= x(x - 1) - 2(x - 1)
= (x - 1)(x - 2)
Therefore, the side lengths are (x - 1) and (x - 2).
In the rectangular figure, the length and width should be the expressions above.
The second equation given is 2x² + x - 6.
= 2x² + x - 6.
= 2x² + 4x - 3x - 6
= 2x(x + 2) - 3(x + 2)
= (2x - 3)(x + 2)
Therefore, the side lengths are (2x - 3) and (x + 2).
In the rectangular figure, the length and width should be the expressions above.
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미안하지만 나는 영어를 잘 몰라, 너는 한국어로 설명해 줄 수 있니?
Answer:
yes u r correct
Hope This Helps! Have A Nice Day!!
6x + 2y = 24....subtract 6x from both sides
2y = -6x + 24...now divide both sides by 2
y = -6/2x + 24/2...now reduce
y = -3x + 12 <=== slope intercept form of y = mx + b
Answer:
HELLO DEAR,
GIVEN:-
10sin⁴A + 15cos⁴A = 6
=> 10(sin²A)² + 15cos⁴A = 6
=> 10{(1 - cos²A)²} + 15cos⁴A = 6
=> 10{1 + cos⁴A - 2cos²A} + 15cos⁴A = 6
=> 10 + 10cos⁴A - 20cos²A + 15cos⁴A = 6
=> 25cos⁴A - 20cos²A + 4 = 0
=> 25cos⁴A - 10cos²A - 10cos²A + 4 = 0
=> 5cos²A(5cos²A - 2) - 2(5cos²A - 2) = 0
=> (5cos²A - 2)(5cos²A - 2) = 0
=> cos²A = 2/5
=> cosA = √2/√5 [ secA = √5/√2]
therefore,
sinA = √[1 - 2/5] = √3/√5 [ cosecA = √5/√3]
now,
27cosec^6A + 8sec^6A
=> 27 × {(√5/√3)²}³ + 8 × {(√5/√2)²}³
=> 27 × 125/27 + 8 × 125/8
=> 125 + 125
=> 250.
HENCE, 27cosec^6A + 8sec^6A = 250.
I HOPE IT'S HELP YOU DEAR,
THANKS
Step-by-step explanation:
