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insens350 [35]
3 years ago
6

Trigonometry

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
5 0

Answer:

cosx = sqrt(15)/4, -sqrt(15)/4

Step-by-step explanation:

cos²x = 1 - sin²sin x

cos²x = 1 - (1/4)²

cos²x = 15/16

cosx = sqrt(15)/4, -sqrt(15)/4

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Erik drives 19.2 miles in 16 minutes.
Katen [24]

Answer:

Erik's average speed exceeds the speed limit by 6.91 miles per hour.

Step-by-step explanation:

Let suppose that Erik travels at constant speed. Hence, the speed (v), measured in miles per hour, is determined by following equation of motion:

v = \frac{s}{t} (1)

Where:

s - Distance, measured in miles.

t - Time, measured in hours.

Please notice that a hour equals 60 minutes. If we know that s = 19.2\,mi and t = 0.267\,h, then the speed of Erik is:

v = \frac{19.2\,mi}{0.267\,h}

v = 71.910\,\frac{mi}{h}

Which is 6.91 miles per hour above the speed limit.

6 0
2 years ago
What is the best way to answer this mixed number 7 3/4 + 1 5/6
olga_2 [115]

9514 1404 393

Answer:

  9 7/12

Step-by-step explanation:

12 is a suitable common denominator.

  (7 3/4) + (1 5/6) = (7 9/12) + (1 10/12) = (7+1) +(9/12 +10/12)

  = 8 + 19/12 = 9 + 7/12 . . . . . . change 19/12 to 1 7/12

  = 9 7/12

_____

My calculator works with mixed numbers very nicely, as many graphing calculators do.

8 0
3 years ago
Read 2 more answers
If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then what is the pr
andreyandreev [35.5K]

If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then the probability of observing at least one car during any 5-minute time interval is 609/2500

Given The probability of observing at least one car on a highway during any 20 minute time interval is 609/625.

We have to find the probability of observing at least one car during any 5 minute time interval.

Probability is the likeliness of happening an event among all the events possible. It is calculated as number/ total number. Its value lies between 0 and 1.

Probability during 20 minutes interval=609/625

Probability during 1 minute interval=609/625*20

=609/12500

Probability during 5 minute interval=(609/12500)*5

=609/2500

Hence the probability of observing at least one car during any 5 minute time interval is 609/2500.

Learn more about probability at brainly.com/question/24756209

#SPJ4

8 0
2 years ago
The bottles of juice that Craig usually buys each have x ounces of juice in them. Another company makes bigger
Tanya [424]

Answer:

27

Step-by-step explanation:

I divided im not 100 percent sure tho

6 0
2 years ago
The value of x is ___<br> °, and the value of y is
PtichkaEL [24]

Answer:

y=50

x=60

Step-by-step explanation:

x= 180-(50+70)

x=60

y=50

4 0
3 years ago
Read 2 more answers
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