Answer:
D={3,9}
The numbers are 3 and 9
Step-by-step explanation:
The set A
={,,,,,,,,,}
Let B be the sub set of A containing odd numbers
B={1,3,5,7,9}
Let C be the sub set of A containing multiply of 3
C= {3,6,9}
Now let D be the be the sub set of A containing both odd numbers and multiples of 3
D={3,9}
Answer:
B) 9
Step-by-step explanation:
6×3/2=9
Since all four terms don't have a common factor we will group them in pairs with common factors.
6uv - 3v^3 + 4u - 2v^2
6uv + 4u - 3v^3 - 2v^2
Take out 2u from the first two terms and -v^2 from the last two terms. The goal is to have a common factor once we take out the GCF's.
2u( 3v + 2) - v^2(3v + 2)
Now we have two terms:
[2u(3v+2)] + [-v^2(3v+2)]
These two terms have a GCF of (3v + 2). Take that out:
(3v + 2)(2u - v^2)
Sector area = (central angle / 360) * PI * radius^2
sector area = (60 / 360) * PI * 25
<span><span><span>sector area = 13.08996939
</span>
square inches
</span> </span><span>sector area = 13.1 (rounded) </span><span>square inches
</span>
