The sum of three consecutive odd integers is 76 less then seven times the middle number. The three integers are 17, 19 and 21 respeectively
<h3><u>Solution:</u></h3>
Since each consecutive odd integer is separated by a difference of 2
Let "n" be the first integer
n + 2 be the second integer
n + 4 be the third integer
Given that the sum of three consecutive odd integers is 76 less then seven times the middle number
Which means,
The sum of ( n, n + 2, n + 4) is equal to 76 less than seven times the middle number ( 7(n + 2))
That is,
n + n + 2 + n + 4 = 7(n + 2) - 76
3n + 6 = 7n + 14 - 76
4n = 68
n = 17
So we get:
First integer = n = 17
Second integer = n + 2 = 17 + 2 = 19
Third integer = n + 4 = 17 + 4 = 21
Thus the three consecutive odd integers are 17, 19 and 21 respeectively
Using Euclid's algorithm, the first number you check is their difference:
60 - 48 = 12
Since 12 divides both numbers evenly, that is your GCF.
_____
If the difference does not divide both numbers evenly, you can repeat the procedure with the difference and the remainder from dividing the smallest of the other numbers by the difference. For example, ...
GCF(60, 44) = GCF(44 mod 16, 16) = GCF(12, 16) = 4
Answer:
Step-by-step explanation:
y = a(b)^x
a would represent the initial value.
b would represent the change
x represents the number of years
y = 805(0.9)^6
y = 805(0.531441)
y = 427.8
y = 427 cheetahs
Answer:
54.56
Step-by-step explanation:
The number after the point is not 5 or higher
