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3 years ago

3 X 5 power or 2

Mathematics

1 answer:

Ainat [17]3 years ago

5 0

225 3x5 is 15 and to the power of 2 is 15x15 so multiply and you get 225 hope it helps

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Differentiate the function with respect to x<br> f(x)= x^4/ x^2- 4<br> Show work

jeyben [28]

Answer:

Step-by-step explanation:

$f(x)=\frac{u}{v} ,u~ and~ v~ functions~ of~ x\\f'(x)=\frac{v ~u'-u~v' }{v^2} \\f(x)=\frac{x^4}{x^2-4} \\f'(x)=\frac{(x^2-4)*4x^3-x^4(2x)}{(x^2-4)^2} \\=\frac{2x^3(2x^2-8-x^2) }{(x^2-4)^2} \\=\frac{2x^3(x^2-8)}{(x^2-4)^2}$

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2 years ago

7- a. What is the radius of the circle with center (3,10) that passes through (12,12)?

loris [4]

Answer: a. Radius of circle = $\sqrt{85}$

b. The equation of this circle : $(x-3)^2+(y-10)^2=85$

Step-by-step explanation:

Given : Center of the circle = (3,10)

Circle is passing through (12,12).

a. To find the radius we apply distance formula (∵ Radius is the distance from center to any point ion the circle.)

Radius of circle = $\sqrt{(12-3)^2+(12-10)^2}$

Radius of circle = $\sqrt{(9)^2+(2)^2}=\sqrt{81+4}=\sqrt{85}$

i.e. Radius of circle = $\sqrt{85}$

b. Equation of a circle = $(x-h)^2+(y-k)^2=r^2$ , where (h,k)=Center and r=radius of the circle.

Put the values of (h,k)= (3,10) and r= $\sqrt{85}$ , we get

$(x-3)^2+(y-10)^2=(\sqrt{85})^2$

$(x-3)^2+(y-10)^2=85$

∴ The equation of this circle : $(x-3)^2+(y-10)^2=85$

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3 years ago

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dezoksy [38]

Answer:

D. is correct!

Step-by-step explanation:

ht tps://us-static.z-dn.net/fil es/ded/302e17a93f9f7dceb0b9635c302342ae.jp g

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2 years ago

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Maru [420]

Answer:

They would be -104 and -103.

Step-by-step explanation:

-103 + (-104)

= -103 - 104

= -207.

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2 years ago

Solve 2x2 - 6x = -8.

erma4kov [3.2K]

Answer:

x=2

Step-by-step explanation:

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2 years ago