Answer:
-7 = -3x + b
Step-by-step explanation:
i'm guessing because you have not provided a visual so i can not determine the B.
Answer:
3p + 0.2r . 2,000
Step-by-step explanation:
Can you give me brainliest
x-coordinates for the maximum points in any function f(x) by f'(x) =0 would be x = π/2 and x= 3π/2.
<h3>How to obtain the maximum value of a function?</h3>
To find the maximum of a continuous and twice differentiable function f(x), we can firstly differentiate it with respect to x and equating it to 0 will give us critical points.
we want to find x-coordinates for the maximum points in any function f(x) by f'(x) =0
Given f(x)= 4cos(2x -π)
In general
from x = 0 to x = 2π :
when k =0 then x = π/2
when k =1 then x= π
when k =2 then x= 3π/2
when k =3 then x=2π
Thus, X-coordinates of maximum points are x = π/2 and x= 3π/2
Learn more about maximum of a function here:
brainly.com/question/13333267
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Answer: -7/8
Step-by-step explanation:
you need to find a common denominator for all of them
in this case it would be 24
2 18/24 -(- 1 12/24) + (-20/24) -(-9/24) - (+ 4 16/24)
2 18/24 + 1 12/24 - 20/24 + 9/24 - 4 16/24
4 6/24 - 20/24 + 9/24 - 4 16/24
3 10/24 + 9/24 - 4 16/24
3 19/24 - 4 16/24
- 21/24
-7/8