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3 years ago

The legs of a isosceles right triangle both measure 10 inches find the length of the hypotenuse

Mathematics

1 answer:

Artist 52 [7]3 years ago

7 0

Answer:

Hypotenuse = 14.1421 inches (rounded off to four decimal values)

Step-by-step explanation:

The legs of an isosceles triangle both measure 10 inches

Since the triangle is a right triangle,

We apply the Pythagorean Theorem to find the height of the hypotenuse

a² + b² = c²

a = 10 inches, b = 10 inches and (c) is the hypotenuse whose value we don't know.

So; 10² + 10² = c²

c² = 100 + 100

c² = 200

c = $\sqrt{200}$ = 14.1421356237 inches

The hypotenuse is 14.1421 inches (answer rounded off to four decimal values)

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15.What must be subtracted from x 3 + 3x-8 to 2x 3 +x 2 -4x+2

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Answer:

Step-by-step explanation:

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3 years ago

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Tanya [424]

Answer:

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Step-by-step explanation:

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3 years ago

The graph of f is given in the figure to the right. Let A(x)equals=Integral from 0 to x f left parenthesis t right parenthesis

Tpy6a [65]

Answer:

$A(4)=-4\pi$

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$A(12)=-4\pi +16$

$A(14)=-4\pi +15$

Step-by-step explanation:

we are given

$A(x)=\int\limits^x_0 f{x} \, dx$

Calculation of A(4):

we can plug x=4

$A(4)=\int\limits^4_0 f{x} \, dx$

Since, this curve is below x-axis

so, the value of integral must be negative

and it is quarter of circle

so, we can find area of quarter circle

radius =4

$A(4)=-\frac{1}{4}\times \pi \times (4)^2$

$A(4)=-4\pi$

Calculation of A(8):

we can plug x=8

$A(8)=\int\limits^8_0 f{x} \, dx$

we can break into two parts

$A(8)=\int\limits^4_0 f{x} \, dx+\int\limits^8_4 f{x} \, dx$

now, we can find area and then combine them

$A(8)=-4\pi +\frac{1}{2}\times 4\times 4$

$A(8)=-4\pi +8$

Calculation of A(12):

we can plug x=12

$A(12)=\int\limits^12_0 f{x} \, dx$

we can break into two parts

$A(12)=\int\limits^4_0 f{x} \, dx+\int\limits^8_4 f{x} \, dx+\int\limits^12_8 f{x} \, dx$

now, we can find area and then combine them

$A(12)=-4\pi +\frac{1}{2}\times 8\times 4$

$A(12)=-4\pi +16$

Calculation of A(14):

we can plug x=14

$A(14)=\int\limits^14_0 f{x} \, dx$

we can break into two parts

$A(14)=\int\limits^4_0 f{x} \, dx+\int\limits^8_4 f{x} \, dx+\int\limits^12_8 f{x} \, dx+\int\limits^14_12 f{x} \, dx$

now, we can find area and then combine them

$A(14)=-4\pi +\frac{1}{2}\times 8\times 4-\frac{1}{2}\times 1\times 2$

$A(14)=-4\pi +16-1$

$A(14)=-4\pi +15$

8 0

2 years ago

If A(−2, 1), B(1, 5), C(4, 4), and D(1, 0) are the vertices of a quadrilateral, do the points form a parallelogram? Justify your

Alexandra [31]

<span>Yes, it is a parallelogram because the slope of segment AB equals the slope of segment DC, which equals negative start fraction four over three end fraction, and AD = BC = 10 units.</span>

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3 years ago

21 = − 6 x − 3 x + 4 + 4 x

horsena [70]

Answer:

x=-17/5

Step-by-step explanation:

1. Simplify -6x-3x+4+4x−6x−3x+4+4x to -5x+4−5x+4.

21=−5x+4

2. Subtract 44 from both sides.

21−4=−5x

3. Simplify 21-4 to 17.

17=-5x

4. Divided both sides by -5.

-17/5=x

5. Switch sides.

x=-17/5

Hope this helps.

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3 years ago