18x6 = 108
110-108 =2
By weeks 6 she will only have $2 left
So being realistic, at week 7 she will have spent all her money.
Step-by-step explanation:
(A) Let a triangle be formed with height of pole h, length of base b and angle of elevation 58°. (Due to lack of a figure).
Tan 58° = h / b = 1.6
(B) Let another triangle be formed with height of pole h, length of base (b + 90) and angle of elevation 36°. (Due to lack of a figure).
Tan 36° = h / (b + 90) = 0.72
(C) <u>Simplifying the two equations</u> :
1.6b = 0.72b + 64.8
b = 64.8 / 0.88 = 73.6 m
h (height of pole) = 1.6 * 73.6 = 117.76 m
Answer: h = 17
Step-by-step explanation: As a general rule, if an equation has any fractions in it, try to get rid of those fractions as soon as possible.
The quickest way to get rid of a fraction is to multiply both
sides of the equation by the denominator of the fraction.
So in this problem, we can get rid of the fraction in our
first step by multiplying both sides of the equation by 4.
On the left, the 4's cancel and on the right, 1(4) is 4.
Now we have h - 13 = 4.
Since 13 is being subtracted from <em>h</em>, to get <em>h</em> by itself,
we need to add 13 to both sides of the equation to get h = 17.
Now, we can check our answer by plugging 17 back
into the original equation shown below in italics.
You know that the ratio of J&S to F&So is 2:3. You need two numbers that have that same ratio to total 60 players. When you multiply both numbers by 12, you have a ratio of 2:3 but the number of players is 24 to 36. Thus, the total players is 60. When looking at the ratio of Juniors to Seniors, the ratio remains 1:2, but must total 24 players. Dividing the total players by 3, you can find where 1 part of the players equals 2 parts of the others. Keeping that same ratio in mind, you are able to calculate that the ratio of Juniors to Seniors is 8:16 but when reduced, still remains a 1:2 ratio.
Answer:
B
Step-by-step explanation
a function has to be on a graph and pass the horizontal line test. if it does not pass it then it will not be a function
