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aleksandrvk [35]

2 years ago

14

Rachel enjoys exercising outdoors. Today she walked 5 2/3 miles in 2 2/3 hours. What is Rachel’s unit walking rate in miles per

hour and in hours per mile?

2 answers:

Dmitriy789 [7]2 years ago

5 0

5 2/3 divided by 2 2/3 = 17/3 divided by 8/3 = 17/8 = 2 1/8 miles per hour

2 2/3 divided by 5 2/3 = 8/3 divided by 17/3 = 8/17 hours per mile

iris [78.8K]2 years ago

5 0

Answer:

5 2/3 divided by 2 2/3 = 17/3 divided by 8/3 = 17/8 = 2 1/8 miles per hour

2 2/3 divided by 5 2/3 = 8/3 divided by 17/3 = 8/17 hours per mile

Step-by-step explanation:

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AnnyKZ [126]

So slope intercept form y=mx+b slope is m

m=6 so
y=6x+b
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put in 3 for x and 4 for y and solve for b
4=6(3)+b
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the slope intercep form is y=6x-14

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4 years ago

Which is not a pair of congruent angles in the diagram below

makvit [3.9K]

BCD and BAD is correct

4 0

3 years ago

Read 2 more answers

Please help I will give brainliest

Katyanochek1 [597]

Answer:

30 in^2

Step-by-step explanation:

The formula for finding the area of a trapezoid is A=a+b/2 x h

In this case, a=5, b=10, and h=4

When you input those values into the formula and solve for A, you get A=30

Please mark as brainliest ;)

3 0

2 years ago

The painting shown at the right has an area of 220. What is the value of x?

tangare [24]

Answer:

9.76

Step-by-step explanation:

area of a rectangle = length * breadth

length = (2x + 3)

breadth = x

given area is 220 sq. inches.

thus,

220 = x * (2x+3)

220 = 2x² +3x

2x² + 3x -220 = 0

x = (-b + √ ( b²-4ac) ) ÷ 2a

x = ( -3 + √ ( 3² - 4*2*220) ) ÷ 2*2

x =9.76

5 0

3 years ago

Consider the equation below. f(x) = 2x3 + 3x2 − 336x (a) Find the interval on which f is increasing. (Enter your answer in inter

Vaselesa [24]

We have been given a function $f(x)=2x^3+3x^2-336x$ . We are asked to find the interval on which function is increasing and decreasing.

(a). First of all, we will find the critical points of function by equating derivative with 0.

$f'(x)=2(3)x^{2}+3(2)x^1-336$

$f'(x)=6x^{2}+6x-336$

$6x^{2}+6x-336=0$

$x^{2}+x-56=0$

$x^{2}+8x-7x-56=0$

$(x+8)-7(x+8)=0$

$(x+8)(x-7)=0$

$x=-8,x=7$

So $x=-8,7$ are critical points and these will divide our function in 3 intervals $(-\infty,-8)U(-8,7)U(7,\infty)$ .

Now we will find derivative over each interval as:

$f'(x)=(x+8)(x-7)$

$f'(-9)=(-9+8)(-9-7)=(-1)(-16)=16$

Since $f'(9)>0$ , therefore, function is increasing on interval $(-\infty,-8)$ .

$f'(x)=(x+8)(x-7)$

$f'(1)=(1+8)(1-7)=(9)(-6)=-54$

Since $f'(1)$ , therefore, function is decreasing on interval $(-8,7)$ .

Let us check for the derivative at $x=8$ .

$f'(x)=(x+8)(x-7)$

$f'(8)=(8+8)(8-7)=(16)(1)=16$

Since $f'(8)>0$ , therefore, function is increasing on interval $(7,\infty)$ .

(b) Since $x=-8,7$ are critical points, so these will be either a maximum or minimum.

Let us find values of f(x) on these two points.

$f(-8)=2(-8)^3+3(-8)^2-336(-8)$

$f(-8)=1856$

$f(7)=2(7)^3+3(7)^2-336(7)$

$f(7)=-1519$

Therefore, $(-8,1856)$ is a local maximum and $(7,-1519)$ is a local minimum.

(c) To find inflection points, we need to check where 2nd derivative is equal to 0.

Let us find 2nd derivative.

$f''(x)=6(2)x^{1}+6$

$f''(x)=12x+6$

$12x+6=0$

$12x=-6$

$\frac{12x}{12}=-\frac{6}{12}$

$x=-\frac{1}{2}$

Therefore, $x=-\frac{1}{2}$ is an inflection point of given function.

3 0

3 years ago