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aleksklad [387]
2 years ago
12

Can you please help me with this question please and i will give you a Brainiest

Mathematics
2 answers:
zhannawk [14.2K]2 years ago
6 0

Answer:

Its the book. Hope it helps.

cestrela7 [59]2 years ago
3 0

stapeler probably that would be my guess try it remember 1 kilo is two pounds

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What is the equation of the line that goes through the points (4,6) and (2,12)?
KengaRu [80]

Answer:

6.72

Step-by-step explanation:

6 0
2 years ago
What is the range of the data? 99.7, 101.8, 103.6,98.6, 100.2, 102.9
erik [133]

Answer:

5.0

Step-by-step explanation:

The data in order looks like so:

98.6, 99.7, 100.2, 101.8, 102.9, 103.6

Take the greatest value and subtract it from the least value to get the range of the data:

103.6-98.6=5

5 is your answer

Hope this helps!

7 0
3 years ago
Read 2 more answers
The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly
Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between \\ (\mu - 6\sigma) and \\ (\mu + 6\sigma). It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

\\ 1 - p = 1 - 0.999999998027 = 0.000000001973

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:

\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697.

The probability of defects is:

\\ 1 - p = 1 - 0.999999426697 = 0.000000573303

Well, the defects present in a six sigma level and a five sigma level are, respectively:

\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}

\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}  

Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>

\\ {6\sigma} \approx \frac{2}{10^9} [1]

\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9} [2]

Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.

8 0
2 years ago
Anna and kim shared 49 jellybeans in the ratio 3:4.Howw many jellybeans did kim receive​
lina2011 [118]
Solution - 49 jellybeans divided by 7 for the ration purposes = 7 so 1/7 the ratio is 7
Therefore Kim having 4/7 is 4 X 7

Answer - 28
4 0
3 years ago
(SUPER EASY) ILL GIVE BRAINLIEST TOO. <br><br> just answer all the questions you know.
IrinaK [193]

Answer: x,y. 2,7, 1,

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
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