Let's use the addition/subtraction method.
Suppose we wish to eliminate variable x.
Mult the first eqn by 5: 10x - 15y = 15
Mult the 2nd eqn by -2: -10x+ 4y = -8
Add these two equations together: -11y = 7, and y = -7/11.
Subst. -7/11 for y in either given equation and find x.
Then your solution is (x,y) (subst. the values we've found for x and y).
Answer:
ONE SOLUTION
Step-by-step explanation:
When two points on a line are given, the equation of the line is given by the formula:
where 
and 
are the points on the line.
Here, the first set of points are: 
and 
.
Therefore, 
and 
.
The line passing through this is given by:
∴ 2x + y - 1 =0
Now, for the second line, the points are:
and 
.
Therefore, 
∴ 2x - y + 2 = 0
Now, to determine the number of solutions the two equations have, we solve these two equations,
Adding Eqn(1) and Eqn(2) we get:
4x = -1
And 
.
Since, we arrive at unique values of 'x' and 'y', we say the lines have only one unique solution.
Answer:
1. no solution
2. one solution
3. infinitely many solutions
Step-by-step explanation:
1. 4= -3
false
2. -5=6c+7
2=6c
c=3
3. 5a+7=5a+7
true
Answer:
Aand C I think ......................
Answer:
85 m
Step-by-step explanation:
The diagonal of a square is √2 times the length of the side. The park will have a side length of 120/√2 m ≈ 84.85 m, about 85 meters.
_____
The relations are ...
diagonal = (√2)×(side length)
side length = diagonal/√2 . . . . . . . . . divide the above equation by √2
