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qaws [65]
4 years ago
9

Are the two triangles similar? If so, how do you know?

Mathematics
2 answers:
lapo4ka [179]4 years ago
6 0

Yes, as the length of the right one is 1.5 longer than the left one

Ainat [17]4 years ago
4 0
Yes because of the length and angle and if u put it on top of eachother it’s the same
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A fighter pilot needs to make an emergency landing. He needs a clear space that is at least 600 m long to land safely. He is fly
Zolol [24]

(a) See the attached sketch. The jet makes a right triangle with the ground with hypotenuse <em>y</em>. Since the angle of depression is 56°, and the plane in which the jet is flying 300 m in the air is parallel with the ground, the angle of elevation in the right triangle is also 56°. Use the definition of sine to solve for <em>y</em>.

sin(56°) = (300 m)/<em>y</em>   →   <em>y</em> = (300 m)/sin(56°)

The uppermost angle in the blue triangle has measure equal to the difference between the two given angles of depression, 56° - 30° = 26°, and the rightmost angle is also 30° by the same reasoning as before. Then by the law of sines,

<em>x</em>/sin(26°) = <em>y</em>/sin(30°)   →   <em>x</em> = sin(26°)/sin(30°) <em>y</em> ≈ 317.2627 m

(b) No, the field is not long enough.

4 0
3 years ago
In a survey of 1000 social-media account holders aged 18 years and older conducted by a certain organization, it was found that
Artyom0805 [142]
We are given with
n = 1000
p = 0.78

Samples = 10
Condition = at most 7 have one or two social media accounts

We can use combinations to solve the problem
P = ∑10Ci (0.78)^i (1-0.78)^(10-i)/ 1000C10 from i from 0 to 7
Solve for P
6 0
3 years ago
Pls help asap will gibe brainlist
MrMuchimi

Answer:

✧ First , I splited the given figure into three parts namely ABCD , EFGH & lastly IJKL ( See the attached picture). Now , We're gonna find out the area of these rectangles :

  • Area of ▭ ABCD = Length × Breadth = 12 × 8 = 96 in²
  • Area of ▭ EFGH = Length × Breadth = 13 × 4 = 52 in²
  • Area of ▭ IJKL = Length × Breadth = 12 × 6 = 72 in²

♨ Now , Adding the area of ▭ ABCD , ▭ EFGH & ▭ IJKL :

☂ Total Area of the figure : 96 in² + 52 in² + 72 in² = \boxed{ \large{ \underline{ \tt{220 \:  {in}^{2} }}}}

☄ Hope I helped! ♡

♪ Have a wonderful day / night ! ♕

✎ \underbrace{ \overbrace{ \mathfrak{Carry \: On \:Learning}}} ☃

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

8 0
3 years ago
Select all of the following true statements if R = real numbers, N = natural numbers, and S = {10, 11, 12,...}.
Fofino [41]

The true statements are:

B. N⊂R

C. S⊂N

D. ∅⊂N

F. {10.11.12,...}⊆S

<h3>Subsets and Sets</h3>

Note that:

  • All real numbers are numbers that can be found on the real number line
  • Natural numbers are positive whole numbers
  • All natural numbers are subsets of real numbers
  • The null set (∅) is a subset of every set
  • A set is a proper subset of itself

Following the points highlighted above, the true statements in the given options re:

B. N⊂R

C. S⊂N

D. ∅⊂N

F. {10.11.12,...}⊆S

Learn more on subsets and sets here: brainly.com/question/13265691

#SPJ1

6 0
2 years ago
Complex zeros of 4x^4-13x^3+31x^2+293x-75
AnnZ [28]
Sorry could you elaborate a bit further on the question

3 0
3 years ago
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