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rjkz [21]
3 years ago
6

Complex zeros of 4x^4-13x^3+31x^2+293x-75

Mathematics
1 answer:
AnnZ [28]3 years ago
3 0
Sorry could you elaborate a bit further on the question

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2. Find the midpoint of a segment<br> connecting the points (a, b) and (4a, 3b).
sasho [114]

Answer:

(2.5a, 2b) your welcome

Step-by-step explanation:

4 0
3 years ago
What is StartFraction 11 Over 12 EndFraction divided by one-third? A fraction bar labeled 1. Under the 1 are 3 boxes labeled one
igor_vitrenko [27]

Answer:

11/12 ÷ 1/3 = 2 and three-fourths

11/12 ÷ 1/3 = 2 3/4

Step-by-step explanation:

What is StartFraction 11 Over 12 EndFraction divided by one-third? A fraction bar labeled 1. Under the 1 are 3 boxes labeled one-third. Under the 3 boxes are 4 boxes containing one-fourth. Under the 4 boxes are 12 boxes containing StartFraction 1 Over 12 EndFraction. 2 and one-fourth 2 and three-fourths 3 and one-third 3 and two-thirds

Given:

11/12 ÷ 1/3

= 11/12 × 3/1

= 33 / 12

= 2 9/12

= 2 3/4

= 2 and three-fourths

11/12 ÷ 1/3 = 2 3/4

3 0
3 years ago
Read 2 more answers
A recipe for beef stew calls for 1 pound of beef and 3 potatoes. The recipe is doubled to include 2 pounds of beef and 6 potatoe
vaieri [72.5K]

To answer the question, let B call the amount of meat and P the number of potatoes.

The recipe says that for every pound of meat we need 3 potatoes.

Then that relationship is written as follows:

1B = 3P

\frac{1}{3}=\frac{P}{B}

If we increase the amounts of the recipe by 100%, it will multiply by 2 the amount of meat and also that of potatoes. Therefore we need 2 pounds of meat and 6 potatoes.

Then the relationship is:

2B = 6P

\frac{2}{6}=\frac{P}{B}

But \frac{2}{6}=\frac{1}{3}

Therefore, the proportion that represents the situation remains the same 1B = 3P

This occurs because the increase in the amount of potatoes and beef was in the same proportion.

6 0
4 years ago
HELP ME OUT PLEASE I RLLY NEED IT ASAP. ):
LenaWriter [7]

(a) Slope is rise over run, or change in y over change in x.

1 -> 3 ( \frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{4 - -8}{-1 - -5} = \frac{4 + 8}{-1 +5}= \frac{12}{4} =\frac{12}{4} )

2 -> 3 ( \frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{1 - 7}{0 - 2} = \frac{-6}{- 2} =\frac{6}{2} )

3 -> -1/3 ( \frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{-7 - -3}{6 - -6}= \frac{-7+3}{6+6}=\frac{-4}{12}=-\frac{1}{3} )

(b) If a line is parallel, the slopes will be the same. If they are perpendicular, the slopes will be are negative reciprocals of one another. If they are neither, then their slopes don't match up in any way.

1 & 2 -> Parallel

1 & 3 -> Perpendicular

2 & 3 -> Perpendicular

     Note - Since 1 & 2 are parallel, then both 1 and 2 will be perpendicular to 3!

Have a nice day!

     If this is not what you are looking for - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

5 0
3 years ago
Read 2 more answers
Please help me with math pleaseeeeee!!!
pav-90 [236]

Answer:

(2, 6) and (-3, -4)

I think, sorry if wrong


Step-by-step explanation:


6 0
4 years ago
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