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3 years ago

Complex zeros of 4x^4-13x^3+31x^2+293x-75

Mathematics

1 answer:

AnnZ [28]3 years ago

3 0

Sorry could you elaborate a bit further on the question

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4. Which statistic can not be determined from a box plot representing the scores on a math test in Mrs. DeRidder's algebra class

adoni [48]

Answer:

the score that occurs most frequently

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2 years ago

Simplify the expression

baherus [9]

2*7b =

use the distributive property

14b

5 0

3 years ago

Read 2 more answers

What is the slope of the line that passes through the points (−10,−4) and (10, -29)?

OleMash [197]

Answer:

slope= - 5/4

Step-by-step explanation:

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2 years ago

What is the center of the ellipse x2+5y2–45=0?

jeka94

Answer:

Center is at (0,0)

Step-by-step explanation:

An equation of ellipse in standard form is:

$\displaystyle{\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2} = 1$

Where center is at point (h,k)

From the equation of $\displaystyle{x^2+5y^2-45=0}$ . First, we add 45 both sides:

$\displaystyle{x^2+5y^2-45+45=0+45}\\\\\displaystyle{x^2+5y^2=45}$

Convert into the standard form with RHS (Right-Hand Side) equal to 1 by dividing both sides by 45:

$\displaystyle{\dfrac{x^2}{45}+\dfrac{5y^2}{45}=\dfrac{45}{45}}\\\\\displaystyle{\dfrac{x^2}{45}+\dfrac{y^2}{9}=1}$

Therefore, the center of ellipse is at (0,0) since there are no values of h and k.

8 0

2 years ago

Find the equation of the line that is perpendicular to the x-axis and passes through the point (-10,-1). Give the full equation

Tomtit [17]

Answer:

x = -10

Step-by-step explanation:

First, determine the slope of the answer. The x-axis is a horizontal line, thus the new line must be vertical. All vertical lines are represented by the equation x = a number. That number represents the x-value of all the points the vertical line passes through.

So, since the line passes through (-10, -1), take the x-value of that point and put it into that equation. Thus, x = -10.

7 0

2 years ago