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Strike441 [17]
3 years ago
12

The frequency of light that has a wavelength of 310 mm

Chemistry
1 answer:
Vilka [71]3 years ago
4 0
Black light hope this helps
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Answer the question PLS 100 points!!!
cluponka [151]
  • 1atm=760mm Hg

Now

  • 1.36atm
  • 1.36(760)
  • 1033.6mm Hg

Done!

5 0
2 years ago
Suppose you are a food chemist working for a company that makes and manufactures soda. Your job is to create a new soft drink wi
Mekhanik [1.2K]

Answer:

The answer to your question is given after the questions so I just explain how to get it.

Explanation:

a)

Get the molecular weight of Phosphoric acid

        H₃PO₄ =  (3 x 1) + (31 x 1) + (16 x 4)

                    = 3 + 31 + 64

                    = 98 g

         98 g -----------------  1 mol

      0.045 g ---------------   x

          x = (0.045 x 1) / 98

          x = 0.045 / 98

          x = 0.00046 moles or 4.6 x 10 ⁻⁴

b)

Molarity = \frac{moles}{volume}

Molarity = \frac{0.00046}{0.35}

Molarity = 0.0013 or 1.31 x 10⁻³

c)

Formula            C₁V₁ = C₂V₂

                              V₁ = C₂V₂ / C₁

Substitution

                              V₁ = (0.0013)(1) / 0.01

Simplification and result

                              V₁ = 0.0013 / 0.1

                              V₁ = 0.13 l = 130 ml            

7 0
3 years ago
Analyze your results.
raketka [301]

#b

According to Le C ha.te llors principle of we increase concentration of reactants or products equilibrium shifts.

  • Yes increases

#c

  • Rate of reaction also increases

#e

Stated in b

3 0
2 years ago
Hello! I just need a little bit of help. I'm supposed to design an experiment on how reaction rates are determined and affected
alexandr1967 [171]
  1. Get 3 cups of water at the exact same temperature, using the thermometer to check.
  2. Label the cups as ‘whole’, ‘pieces’, and ‘crushed’
  3. Next, get something to dissolve, in this case, polident. Take one of the polident tablets and break it into 4 pieces, and set it aside.
  4. Take another polident tablet and this time put it into a different cup, and crush it. Set it aside.
  5. Keep the last tablet whole.
  6. Set up your stopwatch and drop the polident tablet that is whole in the cup labeled ‘whole’, starting the stopwatch at the same time.
  7. Watch the cup and see when the tablet is fully dissolved, then stop the stopwatch.
  8. Record the time in the table.
  9. Repeat steps 6-8 for both the ‘pieces’ and ‘crushed’ tablets.

Hope this helps! Please let me know if you need more help, or if you think my answer is incorrect. Brainliest would be MUCH appreciated. Have a great day!

Stay Brainy!

−xXheyoXx

3 0
2 years ago
A sample of gallium Bromide GaBr2,weighing 0.165 g was dissolved in water and treated with silver nitrate AgNO3, and resulting t
tresset_1 [31]

<u>Answer:</u> The percent gallium in gallium bromide is 30.30 %.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of gallium bromide = 0.165 g

Molar mass of titanium gallium bromide = 229.53 g/mol

Putting values in equation 1, we get:

\text{Moles of gallium bromide}=\frac{0.165g}{229.53g/mol}=0.00072mol

  • The chemical equation for the reaction of gallium bromide and silver nitrate follows:

GaBr_2+2AgNO_3\rightarrow 2AgBr(s)+Ga(NO_3)_2

By Stoichiometry of the reaction:

1 moles of gallium bromide produces 1 mole of gallium nitrate

So, 0.00072 moles of gallium bromide will produce = \frac{1}{1}\times 0.00072=0.00072moles of gallium nitrate

  • Now, calculating the mass of gallium nitrate from equation 1, we get:

Molar mass of gallium nitrate = 193.73 g/mol

Moles of gallium nitrate = 0.00072 moles

Putting values in equation 1, we get:

0.00072mol=\frac{\text{Mass of gallium nitrate}}{193.73g/mol}\\\\\text{Mass of gallium nitrate}=0.139g

Calculating the mass of gallium in the reaction, we use unitary method:

In 1 mole of gallium nitrate, 1 mole of gallium atom is present.

In 193.73 grams of gallium nitrate, 69.72 g of gallium atom is present.

So, in 0.139 grams of gallium nitrate, the mass of gallium present will be = \frac{69.72}{193.73}\times 0.139=g

  • To calculate the percentage composition of gallium in gallium bromide, we use the equation:

\%\text{ composition of gallium}=\frac{\text{Mass of gallium}}{\text{Mass of gallium bromide}}\times 100

Mass of gallium bromide = 0.165 g

Mass of gallium = 0.050 g

Putting values in above equation, we get:

\%\text{ composition of gallium}=\frac{0.050g}{0.165g}\times 100=30.30\%

Hence, the percent gallium in gallium bromide is 30.30 %.

3 0
3 years ago
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