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iren [92.7K]
3 years ago
14

Which of the following is not true of alloys?

Chemistry
1 answer:
Scilla [17]3 years ago
7 0
Option d: copper.

Because copper is an element, not a mixture.

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Write a balanced equation between oxalic acid and potassium hydroxide ​
Salsk061 [2.6K]
2 KOH(aq) + H2C2O4(s) → K2C2O4(aq) + 2 H2O(l) When a sample of oxalic acid (H2C2O4), which is a diprotic acid (both H-atoms are acidic), is titrated with 0.250 M potassium hydroxide solution, 24.66 mL of the potassium hydroxide solution are required to neutralize the acid. I don’t know is this gonna help but ok ._.
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How would you detect sulphur in organic compounds​
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How many grams would 3.36 × 1023 molecules of copper (II) sulfate (CuSO4) weigh?
Semenov [28]
Molar mass ( CuSO₄) = 159.609 g/mol

159.609 g ----------------- 6.02 x 10²³ molecules
         ? g ------------------ 3.36 x 10²³ molecules

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3 0
3 years ago
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does anyone have any advice for breaking up with your gf because you both lost feelings and after months you have been trying to
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advise for to break up with her

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4 0
2 years ago
g When 2.50 g of methane (CH4) burns in oxygen, 125 kJ of heat is produced. What is the enthalpy of combustion (in kJ) per mole
Anna [14]

Answer:

-800 kJ/mol

Explanation:

To solve the problem, we have to express the enthalpy of combustion (ΔHc) in kJ per mole (kJ/mol).

First, we have to calculate the moles of methane (CH₄) there are in 2.50 g of substance. For this, we divide the mass into the molecular weight Mw) of CH₄:

Mw(CH₄) = 12 g/mol C + (1 g/mol H x 4) = 16 g/mol

moles CH₄ = mass CH₄/Mw(CH₄)= 2.50 g/(16 g/mol) = 0.15625 mol CH₄

Now, we divide the heat released into the moles of CH₄ to obtain the enthalpy per mole of CH₄:

ΔHc = heat/mol CH₄ = 125 kJ/(0.15625 mol) = 800 kJ/mol

Therefore, the enthalpy of combustion of methane is -800 kJ/mol (the minus sign indicated that the heat is released).

3 0
2 years ago
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