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2 years ago

Determine the theoretical yield of PbCh2

Chemistry

1 answer:

poizon [28]2 years ago

4 0

Answer:

n(pbo) =mass/molar mass of pbo =2.127/223.2= 9.5 ×10(-3)

= since 1 mole of pbo =1 mole of pbcl2

1 mole of pbcl2 =9.5x10(-3)

therefore n(pbcl2)=mass/molar mass

9.5x10(-3) = mass/278.1

mass = 2.65g

% yeild = actual yeild/ therotical yeildx 100

% yeild = (2.523/2.65g)x 100

% yeild = 95.2%

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Please help make sure its correct thanks

Wewaii [24]

The empirical formula of metal iodide : CoI₃(Cobalt(III) Iodide)

<h3>Further explanation</h3>

13.02 g sample of Cobalt , then mol Co(MW=58.933 g/mol) :

$\tt mol=\dfrac{mass}{Ar}=\\\\mol=\dfrac{13.02~g}{58.933}\\\\mol=0.221$

Mass of metal iodide formed : 97.12 g, so mass of Iodine :

$\tt =mass~metal~iodide-mass~Cobalt\\\\=97.12-13.02\\\\=84.1~g$

Then mol iodine (MW=126.9045 g/mol) :

$\tt \dfrac{84.1}{126.9045}=0.663$

mol ratio of Cobalt and Iodine in the compound :

$\tt 0.221\div 0.663=1\div 3$

5 0

2 years ago

The reaction of ethane gas (C2H6) with chlorine gas produces C2H5Cl as its main product (along with HCl). In addition, the react

Kazeer [188]

Answer:

The percent yield of chloro-ethane in the reaction is 82.98%.

Explanation:

$C_2H_6+Cl_2\rightarrow C_2H_5Cl+HCl$

Moles of ethane = $\frac{300.0 g}{30 g/mol}=10 mol$

Moles of chlorine gases = $\frac{650.0 g}{71 .0 g/mol}=9.1549 mol$

As we can see that 1 mol of ethane react with 1 mole of chlorine gas.the 10 moles will require 10 mole of chlorine gas, but only 9.1549 moles of chlorine gas is present.

This means that chlorine gas is in limiting amount and amount of formation of chloro-ethane will depend upon amount of chlorine gas.

According to reaction , 1 mol of chloro ethane gives 1 mol of chloro-ethane.

Then 9.1549 moles of chlorien gas will give:

$\frac{1}{1}\times 9.1549 mol=9.1549 mol$ of chloro-ethane

Mass of 9.1549 moles of chloro-ethane:

9.1549 mol × 64.5 g/mol = 590.4910 g

Theoretical yield of chloro-ethane: 590.4910 g

Given experimental yield of chloro-ethane: 490.0 g

$\% Yield=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

$\%Yield (C_2H_5Cl)=\frac{490.0 g}{590.4910 g}\times 100=82.98\%$

The percent yield of chloro-ethane in the reaction is 82.98%.

6 0

3 years ago

Why is it important to test the crucible for cracks before heating it?

solmaris [256]

It important to test the crucible for cracks before heating it because it can break while performing the chemical reaction.

The crucible and the lid should be inspected to check for the before heating it to prevent the breaking while performing the reactions. if there are some breaks in the crucible then if we heat the crucible it can lead to breaking of the whole crucible and the material from the crucible to come out and it will come in contact with the lid.

The crucible plays a important role while preforming the reactions, so. it important to check the cracks of the crucible before the heating of the crucible.

To learn more about crucible here

brainly.com/question/10237849

#SPJ4

7 0

1 year ago

PLEASE HELP: Which is the state change that occurs when a solid becomes a gas without becoming a liquid first?

nekit [7.7K]

It is called sublimation

4 0

3 years ago

Which structure is unique to vertebrates?<br> limbs<br> brain<br> skin<br> backbone

IRISSAK [1]

Answer:

Backbone

Explanation:

Organisms that have backbones are known as vertebrates, while the ones without a backbone are classified as invertebrates.

4 0

3 years ago