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2 years ago

Determine the theoretical yield of PbCh2

Chemistry

1 answer:

poizon [28]2 years ago

4 0

Answer:

n(pbo) =mass/molar mass of pbo =2.127/223.2= 9.5 ×10(-3)

= since 1 mole of pbo =1 mole of pbcl2

1 mole of pbcl2 =9.5x10(-3)

therefore n(pbcl2)=mass/molar mass

9.5x10(-3) = mass/278.1

mass = 2.65g

% yeild = actual yeild/ therotical yeildx 100

% yeild = (2.523/2.65g)x 100

% yeild = 95.2%

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