For a hyperbola where the directrix is the line and the focus is at (0, c).
Here, we have c = 5, a² = 9, so b² = 5² - 9 = 16. a = √9 = 3 b = √16 = 4
Your hyperbola's constants are ... a = 3 b = 4
______ Please note that the equation of a hyperbola has a negative sign for one of the terms. The equation given in your problem statement is that of an ellipse.