Answer: If I’m not mistaken, the largest area is 75 m2 and the smallest is 2 m2
Step-by-step explanation:
For both : since they are asking for the area, you should calculate the perimeter.
So for the largest area, since you know that you have 40 fences, and each are 1 meter long, and they’re also asking for the largest rectangular area, this means that only the opposite sides will have the same length, so in order to divide the rectangle with the 40 one-meter fences, the biggest sides have to be 15 meters long (so for both : 15x2=30 meters). Then you deduct from 40, 30 : 40-30 = 10 which then you can devide by 2 and find 5 + 5 and that means that the 2 smallest sides will be 5 meters long each. Then finally to calculate the perimeter you should do the biggest side multiplied by the smallest side : 15 x 5 and you find 75 m2 (squaremeters), if I’m not mistaken.
And for the smallest area you take the smallest possibilities knowing that only the opposite sides should have the same length and not all of them, so you do 1 x 2 and you find 2 m2.
Answer:
x=5.1
Step-by-step explanation:
5x-9+2-4=9.4
5x=9.4+4-2+9
5x=20.4
x=5.1
Answer:
- If the sum is 6, a small cone will be ordered.
- If the sum is 8 or 9, a medium cone will be ordered.
- If the sum is 11, a large cone will be ordered.
Step-by-step explanation:
The table below shows the possible outcomes from drawing two balls. We see the relative frequencies to be ...
6: 4
8: 2
9: 2
11: 4
To make a fair decision, we want the relative frequencies of the decision possibilities to be the same. If we combine sums 8 and 9 to one category (medium cone, for example), then 6, (8 or 9), and 11 will all have the same relative frequency: 4.
The appropriate "fair decision" choice is ...
6: small cone
8 or 9: medium cone
11: large cone
Answer:
y=4
Step-by-step explanation:
