Answer:
Increase
Explanation:
The predator is a type of animal or bird species which kill other animals to obtain its food. The prey is the animal which is killed by the predator. According to the given situation, if the predator species A is eliminated, the population of the predator B will likely increase because there will be no competition between the two species for the same prey. And the chances of predator B obtaining the prey will increase. Hence, the population will increase.
If Jerry wants to start a small business producing jelly made from marine algae he should select red algae for this purpose. Red algae is a major staple in some Asian and European cuisines.
The right answer is metaphase II.
The process is performed in two nuclear and cytoplasmic divisions, called first and second meiotic division or simply meiosis I and meiosis II. Both include prophase, metaphase, anaphase, and telophase. First division prophase is long and consists of 5 stages: leptotene, zygotene, pachytene, diplotene, and diakinesis. It is at this point that genetic recombination takes place at the level of chiasmus.
During meiosis I, the members of each homologous pair of chromosomes are paired during prophase, forming bivalents. During this phase, a protein structure, called synaptonemal complex form, allows recombination between homologous chromosomes. Subsequently, a large condensation of the bivalent chromosomes occurs and go to the metaphase plate during the first metaphase, resulting in the migration of n chromosomes to each of the poles during the first anaphase. This reduction division is responsible for maintaining the number of chromosomes characteristic of each species.
In meiosis II, as in mitosis, the sister chromatids comprising each chromosome are separated and distributed between the nuclei of the daughter cells. Between these two successive steps, there is no DNA replication. The maturation of the daughter cells will result in the gametes.
