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andrew-mc [135]
3 years ago
15

Trevor sees 8 red birds. He sees 5 more red birds than blue birds hkw many. Blue birds does trevor see

Mathematics
2 answers:
dybincka [34]3 years ago
3 0
Trevor would see 3 blue birds because 8-5=3
Aleks04 [339]3 years ago
3 0
3 blue birds since there all
Red
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Marta_Voda [28]
You would split the rope by 1/3
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la. There is 1/3 gallon of water in a 3-gallon container. What fraction of the container is filled write as a fraction​
ahrayia [7]

1/3 of a gallon divided by 3 gallons = 1/9

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2 years ago
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Rewrite the following quadratic functions in intercept or factored form. Show your work.
Vlad [161]

Answer:

y = (2x + 3)(2x + 3) = (2x + 3)²

Step-by-step explanation:

We are given a quadratic function and we have to write it in factored form.

y = 9 + 12x + 4x²

y = 4x² + 12x + 9

We can break the mid-term in such a way that when they are multiplied, the factors give a product of 36x² and when added, they give a result of 12x, as show below:

y = 4x² + 6x + 6x + 9

Taking 2x common from the first two variables and 3 from the second two

y = 2x(2x + 3) + 3(2x + 3)

Taking 2x+3 common

y = (2x + 3)(2x + 3) = (2x + 3)²

3 0
3 years ago
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It’s a new semester!students are grouped into three clubs, which each has 10,4 and 5 students.In how many ways can teacher sleep
My name is Ann [436]

The total number of ways to select 2 students from the 3 clubs is 55 ways.

Since there are three clubs which each has 10, 4 and 5 students, and we require the number of ways a teacher can select 2 students so that they are from different clubs.

Since order doesn't matter and anybody can be chosen first, we use combination theory.

<h3 /><h3>Number of ways of selecting from the first two clubs</h3>

Since we have two slots, to select the first person from the first club, we ¹⁰C₁. For the second student from the club of 4, we have ⁴C₁. Also, there are 2 ways of selecting the two students.

So, there are ¹⁰C₁ × ⁴C₁/2!

= 10 × 4/2

= 20 ways from the first two clubs.

<h3 /><h3>Number of ways of selecting from the next two clubs</h3>

For the next two clubs of 4 and 5 students, for the first slot, we have ⁴C₁. For the second student, we have ⁵C₁. Also, there are 2 ways of selecting the two students.

So, there are ⁴C₁ × ⁵C₁/2!

= 4 × 5/2

= 10 ways from the next two clubs.

<h3 /><h3>Number of ways of selecting from the last two clubs</h3>

For the first and last club of 10 and 5 students, for the first slot, we have ¹⁰C₁. For the second student, we have ⁵C₁.  Also, there are 2 ways of selecting the two students.

So, there are ¹⁰P₁ × ⁵P₁/2!

= 10 × 5/2

= 25 ways from the first and last club.

<h3 /><h3>Total number of ways of selecting two students from the 3 clubs.</h3>

So, the total number of ways to select 2 students from the 3 clubs is 20 + 10 + 25 = 55 ways.

So, the total number of ways to select 2 students from the 3 clubs is 55 ways.

Learn more about combinations here:

brainly.com/question/25990169

7 0
2 years ago
Please help me fast, I will give brainliest to whoever shows there work, and if it is right.
Sunny_sXe [5.5K]

Answer:

The required equation is \frac{3}{2}x-3=y

Step-by-step explanation:

The equation of the given function can be written in the form y=mx+b, where m is the slope and b is the y-intercept.

The given equation has a y-intercept of b=-3


The straight line passes through (0,-3) and (2,0).


We calculate the slope using the formula,

m=\frac{y_2-y_1}{x_2-x_1}


m=\frac{0--3}{2-0}


m=\frac{0+3}{2-0}


m=\frac{3}{2}


We now substitute the slope and y-intercept into the above equation of the straight line to get,


y=\frac{3}{2}x-3

This is the same as


\frac{3}{2}x-3=y



6 0
3 years ago
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