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andrew-mc [135]
3 years ago
15

Trevor sees 8 red birds. He sees 5 more red birds than blue birds hkw many. Blue birds does trevor see

Mathematics
2 answers:
dybincka [34]3 years ago
3 0
Trevor would see 3 blue birds because 8-5=3
Aleks04 [339]3 years ago
3 0
3 blue birds since there all
Red
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11B. Long Beach Towing Company charges $40 plus $5 per mile to
gavmur [86]

Answer:

The charges will be the same after 10 miles.

Step-by-step explanation:

Long Beach Towing Company:

Charges $40 plus $5 per mile. So after x miles, the charge will be of:

L(x) = 40 + 5x

Five-Star Towing Company:

Chargers of $70 plus $2 per mile. So after x miles, the charge will be of:

F(x) = 70 + 2x

After how many miles the charges for the two companied will be the same?

This is x for which:

L(x) = F(x)

So

40 + 5x = 70 + 2x

5x - 2x = 70 - 40

3x = 30

x = \frac{30}{3}

x = 10

The charges will be the same after 10 miles.

5 0
2 years ago
The cost of a concert ticket last week was $50.00. This week a concert ticket is $55.00. The percent increase of the ticket from
marta [7]

Answer:

110% pls give brainliest

Step-by-step explanation:

4 0
2 years ago
What is the answer to number 18?
dmitriy555 [2]

Answer: 3n ×9

Step-by-step explanation:

The product of 3 times a N number equals 3n or 3 ×N but you should write 3n then times it by 9

7 0
3 years ago
The area of the rug is 4 15/36<br> The rug is 2 3/4 meters in height <br> How wide is the rug
sineoko [7]
I assume the rug is rectangle.

The area of rectangle is width (W) multiply by hight (H)

A=4\frac{15}{36}=4\frac{5\cdot3}{12\cdot3}=4\frac5{12}\\\\H=2\frac34\\\\\\A=W\cdot H\\\\4\frac{5}{12}=W\cdot2\frac34\\\\4\frac5{12}:2\frac34=W\\\\ \frac{4\cdot12+5}{12}:\frac{2\cdot4+3}{4}=W\\\\ \frac{53}{12}:\frac{11}4=W\\\\ \frac{53}{12}\cdot\frac4{11}=W\\\\ \frac{53\cdot4}{3\cdot4\cdot11}=W\\\\W=\frac{53}{33}\\\\W=1\frac{20}{33}

The rug is  1\frac{20}{33}  meters wide
4 0
3 years ago
All the boxes in a certain warehouse were arranged in stacks of 12 boxes each, with no boxes left over. After 60 additional boxe
AveGali [126]

Answer:

(1) There were fewer than 110 boxes in the warehouse before the 60 additional boxes arrived. (2) There were fewer than 120 boxes in the warehouse after the 60 additional boxes arrived.

Step-by-step explanation:

Given that all the boxes in a certain warehouse were arranged in stacks of 12 boxes each, with no boxes left over.

This implies that boxes are in multiples of 12

i.e. 12, or 24, or 36 or....

Let us say this as 12m for m an integer

Now additional boxes arrived =60

Total number of boxes now = 12m+60

This when arranged in stacks of 14,nothing left out

Or this is multiple of 14

12m+60 = 14n for some positive integer n.

By trial and error we find that if 60 is to be divided by 14, 24 should be added and 24 is a multiple of 12.

So we say originally 24 boxes were there now 84 boxes there.

Hence both options are right.

(1) There were fewer than 110 boxes in the warehouse before the 60 additional boxes arrived. (2) There were fewer than 120 boxes in the warehouse after the 60 additional boxes arrived.

3 0
3 years ago
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