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3 years ago

Hi I need help on my math the mid-chapter checkpoint

Mathematics

1 answer:

masya89 [10]3 years ago

8 0

Answer:

do you know how to divide without a calculator? you should really learn...but here 3=211,4=60.875,5=410.25,6=307.23

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What unknown number makes 7 x 8 true<br> please answer it in 5 minutes

katen-ka-za [31]

The answer would be 56

4 0

2 years ago

Are these ratios equivalent 18: 8 and 20:14

Allisa [31]

Answer:

Step-by-step explanation:

-18:8 can be simplified to 9:4

-20:14 can be simplified to 10:7

-9:4 does not equal 10:7

7 0

3 years ago

Read 2 more answers

. Find two polynomial expressions whose quotient, when simplified, is 1/x . Use that division problem to determine whether polyn

Sergeeva-Olga [200]

Answer:

The two polynomials are:

(x + 1) and (x² + x)

Step-by-step explanation:

A polynomial is simply an expression which consists of variables & coefficients involving only the operations of addition, subtraction, multiplication, and non - negative integer exponents of variables.

Now, 1 and x are both polynomials. Thus; 1/x is already a quotient of a polynomial.

Now, to get two polynomial expressions whose quotient, when simplified, is 1/x, we will just multiply the numerator and denominator by the same polynomial to get more quotients.

So,

Let's multiply both numerator and denominator by (x + 1) to get;

(x + 1)/(x(x + 1))

This gives; (x + 1)/(x² + x)

Now, 1 and x are both polynomials but the expression "1/x" is not a polynomial but a quotient and thus polynomials are not closed under division.

6 0

3 years ago

A school debate team has 4 girls and 6 boys. A total of 3 of the team members will be chosen to participate in the district deba

mariarad [96]

There are 4+6=10 people in the team.
First calculate in how many ways you can choose 3 people from a group of 10 people, using combination:
$(^{10} _3)=\frac{10!}{3!(10-3)!}=\frac{10!}{3! \times 7!}=\frac{7! \times 8 \times 9 \times 10}{6 \times 7!}=\frac{8 \times 9 \times 10}{6}=\frac{720}{6}=120$
You can choose 3 people in 120 ways.

You can select 1 girl from a group of 4 girls in 4 ways.
Calculate in how many ways you can choose 2 boys from a group of 6 boys:
$(^6 _2)=\frac{6!}{2! (6-2)!}=\frac{6!}{2! \times 4!}=\frac{4! \times 5 \times 6}{2 \times 4!}=\frac{5 \times 6}{2}=\frac{30}{2}=15$
You can choose 2 boys in 15 ways.
Using the rule of product, you can calculate that you can choose 1 girl and 2 boys in 4×15=60 ways.

The probability of choosing 1 girl and 2 boys is the number of ways you can choose 1 girl and 2 boys divided by the number of ways you can choose 3 people from the group.
$P=\frac{60}{120}=\frac{1}{2}=50\%$

The probability is 1/2, or 50%.

4 0

3 years ago

3x + 2y = 4

arlik [135]

3x + 2y = 4
2y = -3x + 4
Divide by 2
Solution: y = -3/2x + 2

x + 2y = -4
2y = -x - 4
Divide by 2
Solution: y = -1/2x - 2

6 0

3 years ago