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ella [17]
3 years ago
11

Can someone help me with this question please!!!!!

Mathematics
1 answer:
faltersainse [42]3 years ago
6 0
From the equation, it looks like we can set up a triangle like this.  One side is x and the other is x + 20 because the northbound car traveled 20 miles farther.  The hypotenuse is 100 because they were 100 miles apart.

Next, we can use the Pythagorean Theorem to solve for x:

a² + b² = c²
x² + (x + 20)² = 100²

This simplifies to:

x² + x² + 40x + 400 = 10000
2x² + 40x = 9600
2x² + 40x - 9600 = 0

After that, we can divided each side by 2:

x² + 20x - 4800 = 0

Next, we have to factor:

(x - 60)(x + 80) = 0
x = 60, -80

Since we know that distance can't be negative, 60 is the valid answer in this case.

x = 60
x + 20 = 80

Using this information, we know that the westbound car traveled 60 miles and the northbound car traveled 80 miles.

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211.1336 rounded to nearest tenth
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Answer:

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Step-by-step explanation:

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Use f’( x ) = lim With h ---> 0 [f( x + h ) - f ( x )]/h to find the derivative at x for the given function. 5-x²
beks73 [17]
<h2>Answer:</h2>

The derivative of the function f(x) is:

                 f'(x)=-2x

<h2>Step-by-step explanation:</h2>

We are given a function f(x) as:

f(x)=5-x^2

We have:

f(x+h)=5-(x+h)^2\\\\i.e.\\\\f(x+h)=5-(x^2+h^2+2xh)

( Since,

(a+b)^2=a^2+b^2+2ab )

Hence, we get:

f(x+h)=5-x^2-h^2-2xh

Also, by using the definition of f'(x) i.e.

f'(x)= \lim_{h \to 0} \dfrac{f(x+h)-f(x)}{h}

Hence, on putting the value in the formula:

f'(x)= \lim_{h \to 0} \dfrac{5-x^2-h^2-2xh-(5-x^2)}{h}\\\\\\f'(x)=\lim_{h \to 0} \dfrac{5-x^2-h^2-2xh-5+x^2}{h}\\\\i.e.\\\\f'(x)=\lim_{h \to 0} \dfrac{-h^2-2xh}{h}\\\\f'(x)=\lim_{h \to 0} \dfrac{-h^2}{h}+\dfrac{-2xh}{h}\\\\f'(x)=\lim_{h \to 0} -h-2x\\\\i.e.\ on\ putting\ the\ limit\ we\ obtain:\\\\f'(x)=-2x

      Hence, the derivative of the function f(x) is:

          f'(x)=-2x

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