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3 years ago

Use the definition of the derivative to find f'(x) for f(x)=3x^2-5x+2

Mathematics

1 answer:

Butoxors [25]3 years ago

8 0

The derivative is 6x-5

Hope this helps

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It takes 54 minutes for 4 people to paint 6 walls. How many minuets does it take 6 people to paint 7 walls?

earnstyle [38]

It takes 42 minutes for 6 people to paint 7 walls

Solution:

It takes 54 minutes for 4 people to paint 6 walls

To find: Minutes required for 6 people to paint 7 walls

If $M_1$ men can do $W_1$ work in $D_1$ days working $H_1$ hours per day and $M_2$ men can do $W_2$ work in $D_2$ days working $H_2$ hours per day, then

$\frac{M_1D_1H_1}{W_1} = \frac{M_2D_2H_2}{W_2}$

M = Number of men

D = Number of days

H = Number of hours per day

W = Amount of work

Here in this sum,

54 minutes for 4 people to paint 6 walls

$H_1 = 54 minutes ; M_1 = 4 people ; W_1 = 6 walls$

Minutes required for 6 people to paint 7 walls

$H_2 = ? ; M_2 = 6 people ; W_2 = 7 walls$

Substituting the values in formula, we get

$\frac{54 \times 4}{6} = \frac{H_2 \times 6}{7}\\\\9 \times 4 = \frac{H_2 \times 6}{7}\\\\H_2 = \frac{36 \times 7}{6}\\\\H_2 = 42$

Thus it takes 42 minutes for 6 people to paint 7 walls

7 0

3 years ago

Pls help ASAP i don’t have time!!!!!

Lesechka [4]

Answer:

Step-by-step explanation:

Let the width be W.

14w=(8*10)

14w=80

The width of the frame needs to be at least 5.7 inches.

6 0

2 years ago

Circle 1 is centered at (−4, 5) and has a radius of 2 centimeters. Circle 2 is centered at (2, 1) and has a radius of 6 centimet

IgorC [24]

Basically, you have two circles. You are asked to take circle 1 and "move it" so that it is on top of circle 2. This process of moving is called a translation and can be thought of as sliding. You do this by ensuring that the two have the same center. So, starting at (-4,5) how do you have to move to end up at (2,1)?

To do this we need to move right 6 as the x-coordinate goes from -4 to 2. We also need to move down 4 as the y-coordinate goes from 5 to 1. So we add 6 to the x-coordinate and subtract 4 from the y-coordinate. The transformation rule is (x+6, y-4).

Once you do this the circles have the same center. Next you wish to dilate circle 1 so it ends up being the same size at circle 2. That means you stretch it out in such a way that it keeps its shape. Circle 1 has a radius of 2 centimeters and circle 2 has a radius of 6 centimeters. That is 3x bigger. So we dilate by a factor of 3.

Translations and dilations (along with reflections and rotations) belong to a group known as transformations.

3 0

3 years ago

Write the equation -4x^2+9y^2+32x+36y-64=0 in standard form. Please show me each step of the process!

IgorC [24]

Hey there, hope I can help!

$-4x^2+9y^2+32x+36y-64=0$

$\mathrm{Add\:}64\mathrm{\:to\:both\:sides} \ \textgreater \ 9y^2+32x+36y-4x^2=64$

$\mathrm{Factor\:out\:coefficient\:of\:square\:terms} \ \textgreater \ -4\left(x^2-8x\right)+9\left(y^2+4y\right)=64$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4$
$-\left(x^2-8x\right)+\frac{9}{4}\left(y^2+4y\right)=16$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}9$
$-\frac{1}{9}\left(x^2-8x\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}$

$\mathrm{Convert}\:x\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x^2-8x+16\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert}\:y\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y+4\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Refine\:}\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right) \ \textgreater \ -\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=1$

$Refine\;once\;more\;-\frac{\left(x-4\right)^2}{9}+\frac{\left(y+2\right)^2}{4}=1$

For me I used
$\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}= 1$
$As\;\mathrm{it\;\:is\:the\:standard\:equation\:for\:an\:up-down\:facing\:hyperbola}$

I know yours is an equation which is why I did not go any further because this is the standard form you are looking for. I would rewrite mine to get my hyperbola standard form. However the one I have provided is the form you need where mine would be.
$\frac{\left(y-\left(-2\right)\right)^2}{2^2}-\frac{\left(x-4\right)^2}{3^2}=1$

Hope this helps!

4 0

3 years ago

Tri-Star Industries employs electrical, plumbing, and air conditioning technicians. Their home office is made up of three square

Molodets [167]

Answer:

6084 $\text{ft}^2$ .

Step-by-step explanation:

Please find the attachment.

We have been given that the home-office of Tri-star industries is made up of three square buildings, one for each department, with a triangular atrium in the middle. The area of the Plumbing building is 5,184 $\text{ft}^2$ and the area of the A/C building is 900 $\text{ft}^2$ .

We know that area of square is square of its side length. Since all building are squares, so to find the area of electrical building, we will use Pythagoras theorem.

$a^2+b^2=c^2$

We can see from our attachment that side length of electrical building is hypotenuse (c) of the right triangle.

Upon substituting our given information in Pythagoras theorem, we will get:

$5184+900=c^2$

$6084=c^2$

Therefore, the area of electrical building is 6084 square feet.

3 0

3 years ago