Answer:
The interquartile range is <em>50.</em>
Step-by-step explanation:
To find our answer we have to first <em>quartile 1</em> and <em>quartile 3</em> are equal too. When we look at the plot <em>quartile 1 </em>is equal to <em>20,</em> <em>quartile 3 </em>is equal to <em>70</em> because it is in between <em>60</em> and <em>80</em>. Now to find the interquartile range we will <em>subtract 70</em> from <em>20</em> and we get <em>50</em>. Therefore, <u><em>50</em></u><em> is our answer.</em>
Answer:
2.5 pi
Step-by-step explanation:
Comment
If you were trying to get the area of a whole circle, you would use
Area = pi r^2
You have to modify the formula to show that just part of the circle has an area that you are interested in.
The new formula is
Area = (theta/360) pi r^2
Givens
r = 30 cm
theta = 100
Solution
Area = (100 / 360) * pi * r^2 Substitute the givens into this formula
Area = (5 / 18) * pi * 3^2 Expand
Area = (5 / 18) * pi * 9 Cancel 9 into 18
Area = 5/2 * pi
Area = 2.5 * pi
Answer:
75
Step-by-step explanation:
Answer:
14-3n
Step-by-step explanation:
FVAD=515[((1+0.18/12)^(12*2)-1)/(0.18/12)]*(1+0.18/12)
FVAD=14967.46
