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3 years ago

Past half hour of 6?

Mathematics

2 answers:

katrin2010 [14]3 years ago

4 0

What do you mean by this ?
Half past six is 6:30 I'm not sure what you are seeking..

SVEN [57.7K]3 years ago

4 0

Past half hour of 6 is 5:30

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A flagpole casts a shadow that is 85 feet long. Paul is 6 feet tall, and while standing next to the flagpole, casts a shadow tha

hammer [34]

Answer:

51m

Step-by-step explanation:

-Paul is 6ft, and has a 10ft shadow. The pole has a 85ft shadow:

-Using ratios:

$\frac{Height\ of \ object}{Height\ of \ shadow}$

Let h be the height of the flagpole:

$=>\frac{6}{10}=\frac{h}{85}\\\\h=\frac{6\times 85}{10}\\\\h=51$

Hence, the height of the pole is 51m

6 0

3 years ago

Help thanks 7.04 love u guys

Ugo [173]

Answer:

D. $-\frac{3}{4}$

Step-by-step explanation:

The given equation is

$4y=8x-3$

When we divide through by 4 we get;

$y=2x-\frac{3}{4}$

Comparing to

y=mx+c,

The y-intercept is $-\frac{3}{4}$

The corrrect choice is D.

3 0

3 years ago

Read 2 more answers

Select all that apply.

Lelechka [254]

Answer: The second option and the third option are true.

Step-by-step explanation:

The formula of the line in slope-intercept form is:

$y=mx+b$

Where m is the slope and b is the y-intercept.

By definition, the y-intercept in a direct variation is 0.

Therefore, substituting $m=-3$ and $b=0$ into the equation, you obtain:

$y=-3x+0$

Then, the equation is:

$y=-3x$

As this is a line, it is a linear function.

Therefore, the second option and the third option are true.

8 0

3 years ago

What is the solution to this system of linear equations?

svetoff [14.1K]

It’s B
If y-x=6
Y +X =_10
then y= 6 + x, instead of y insert this no
6+ x+ x =-10
6 + 2x =-10 then collect like terms
2x =-10-6
2x=-16 then multiple both side by 1/2
X=-8
Y=6+x instead of x insert -8
Y=6-8
=-2

7 0

3 years ago

Factor: (m+2)^2−(m+2)+mn·(n+2)+2n(n+2)

bazaltina [42]

ANSWER
${(m + 2)}( {n}^{2} + 2n + m + 1)$

EXPLANATION

The given expression is

${(m + 2)}^{2} - (m + 2) + mn(n + 2) + 2n(n + 2)$

We factor to get,

$= {(m + 2)}(m + 2 - 1) +n (n + 2) (m+ 2)$

This implies that,

$= {(m + 2)}(m + 1) +n (n + 2) (m+ 2)$

We factor further to obtain,

$= {(m + 2)}((m + 1) +n (n + 2))$

or

$= {(m + 2)}( {n}^{2} + 2n + m + 1)$

5 0

3 years ago