5/7 +1/3
find the common denominator for both of the fractions
common denominator is 21
mutiply by 3 for 5/7
(5)(3)/(7/(3)= 15/21
mutiply by 7 for 1/3
(1)(7)/(3)(7)= 7/21
15/21+7/21
add the numerators
15+7= 22
denominator stays the same -21
Answer:
22/21 or 1 1/21
Answer:A) What are the side lengths of the original triangle, ABC?
B) What are the side lengths of the enlarged, A’B’C?
C) Calculate the area and the perimeter of A’B’C.
6x - 4y = 8...solve for x
6x = 4y + 8
x = (4/6)y + 8/6
x = 2/3y + 4/3 <==
A=36 1/2*8*9 this is how you would figure out A
