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katovenus [111]
3 years ago
5

Can someone help me please it’s urgent

Mathematics
1 answer:
laila [671]3 years ago
7 0

Answer:

use the x and y method and try to apply it with the 3 given expressions

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For the right triangle shown, the lengths of two sides are given. find the third side. leave your answer in simplified, radical
Citrus2011 [14]
There is no diagram
6 0
2 years ago
KLMN is a parallelogram,
Aleonysh [2.5K]

Answer:

Ok soo.

Step-by-step explanation:

sum of two adjacent angles of parallelogram is 180

so angle K + angle L = 180

as AK bisects angle K and LA bisects angle L

so, angle AKL + angle ALK = 180 /2 = 90

in triangle AKL,

angle AKL + angle ALK+angle KAL = 180(sum of all angles in triangle = 180)

so, from above two equations,

angle KAL = 90

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4 0
3 years ago
A square is removed from the right hand corner
denis-greek [22]

Answer:

C im pretty sure

Step-by-step explanation:

Because the square taken out has a 4x4 area which is 16 and the area of the whole square used to be 14x14 which is 196 and if u subtract 16 from that you get 180

5 0
3 years ago
Read 2 more answers
How do you solve 4b^2+8b+7=4 using the quadratic formula
lina2011 [118]

4b^2+8b+7=4\\
4b^2+8b+3=0\\\\
x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\
x=\dfrac{-8\pm\sqrt{8^2-4\cdot4\cdot3}}{2\cdot4}\\
x=\dfrac{-8\pm\sqrt{64-48}}{8}\\
x=\dfrac{-8\pm\sqrt{16}}{8}\\
x=\dfrac{-8\pm4}{8}\\
x=\dfrac{-2\pm1}{2}\\
x=\dfrac{-1}{2 }\vee x=\dfrac{-3}{2}\\
x=-\dfrac{1}{2 }\vee x=-\dfrac{3}{2}
4 0
3 years ago
Read 2 more answers
A. 22.1 ft^2<br> B. 20 ft^2<br> C. 13.5 ft^2<br> D. 16.8 ft^2
USPshnik [31]
The answer would be D, 16.8 ft.^2
4 x 2.5 + 2^2 x 3.14 x .5= 16.8
8 0
3 years ago
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