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Margarita [4]
3 years ago
7

There are 20 bicycles and 10 cars parked in the parking lot. Each bicycle had two wheels and each car had four wheels. How many

wheels are there in total?
Mathematics
2 answers:
Sliva [168]3 years ago
6 0
20(2) + 10(4)
40 + 40
80

There are 80 wheels in total

hope this helps
AlexFokin [52]3 years ago
6 0
20 × 2 = 40 bicycle wheels
10 × 4 = 40 car wheels
40 + 40 = 80 wheels total
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Ms. Gonzales gathered data on the number of vowels in the first and last names of each of her students. The data are shown in th
Svetllana [295]
Where s the data of the students
7 0
2 years ago
Help please!!! really really important​
Serga [27]

Answer:

42. Graph a

43. Not possible.

44. Graph e

45. Graph c

46. Graph b.

Step-by-step explanation:

42. 7x + 13 ≥ 55

⇒ x ≥ 6

So, it matches graph a.

43. 12x - 8 > 4(3x + 2)

⇒ 12x - 8 > 12x + 8

Hence, d. not possible.

44. \frac{x}{- 4} - 3 < - 1

⇒ \frac{x}{- 4} < 2

⇒ x > - 8

Hence, graph e matches.

45. - 4(- 2x + 3) ≤ 5 + 8x

⇒ 8x - 12 ≤ 5 + 8x

⇒ - 12 ≤ 5

This is true for all values of x, hence that matches graph c.

46. - 4(x + 3) > 8(x + 3)

⇒ - 4x - 12 > 8x + 24

⇒ 12x < - 36

⇒ x < - 3

Hence, graph b matches the situation. (Answer)

4 0
3 years ago
Drag the dots to plot (5.5, 4), (-7,1), and (0,–9).<br> y
AURORKA [14]

5.5 always goes between 5 and 6

remember (x,y) one of the dots goes on the exactly on the axis, you have to drag it down to -9 from the y-axis

3 0
2 years ago
A small regional carrier accepted 23 reservations for a particular flight with 20 seats. 14 reservations went to regular custome
MrRissso [65]

Answer:

- The probability that overbooking occurs means that all 8 non-regular customers arrived for the flight. Each of them has a 56% probability of arriving and they arrive independently so we get that  

P(8 arrive) = (0.56)^8 = 0.00967

- Let's do part c before part b. For this, we want an exact booking, which means that exactly 7 of the 8 non-regular customers arrive for the flight. Suppose we align these 8 people in a row. Take the scenario that the 1st person didn't arrive and the remaining 7 did. That odds of that happening would be (1-.56)*(.56)^7.

Now take the scenario that the second person didn't arrive and the remaining 7 did. The odds would be  

(0.56)(1-0.56)(0.56)^6 = (1-.56)*(.56)^7. You can run through every scenario that way and see that each time the odds are the same. There are a total of 8 different scenarios since we can choose 1 person (the non-arriver) from 8 people in eight different ways (combination).  

So the overall probability of an exact booking would be [(1-.56)*(.56)^7] * 8 = 0.06079

- The probability that the flight has one or more empty seats is the same as the probability that the flight is NOT exactly booked NOR is it overbooked. Formally,  

P(at least 1 empty seat) = 1 - P(-1 or 0 empty seats)  

= 1 - P(overbooked) - P(exactly booked)

= 1 - 0.00967 - 0.06079  

= 0.9295.

Note that, the chance of being both overbooked and exactly booked is zero, so we don't have to worry about that.

Hope that helps!

Have a great day :P

7 0
3 years ago
The value of x is and the value of y is
TEA [102]

Answer:

x = 60, y = 50

Step-by-step explanation:

60 + 50 = 110 + 70 = 180.

50 + 70 = 120 + 6 = 180.

Therefore 50 + 70 + x = 60

Therefore 70 + 60 + y = 50

6 0
3 years ago
Read 2 more answers
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