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3 years ago

Which mixes number is equivalent to the improper fraction 17/10

Mathematics

1 answer:

Romashka [77]3 years ago

8 0

1 7/10 is equivalent to the improper fraction 17/10

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Which of the following is the solution set to the inequality −25x+14>20? Select one: A. x < -64 B. x > -64 C. x < -1

Sindrei [870]

Answer:

x< -0.24

Step-by-step explanation:

So this is going to sound stupid, but I got x< -0.24 which is just not an option, but this is how I got it...

-25x+14>20

subtract 14 from each side

-25x>6

divide each side by -25

x< -0.24

I switch the way the sign was facing bc I divided by a negative.

Now I know that this must be wrong, but it makes the most sense because I am pretty sure I did all of the math right. Sorry this probably didnt help , but I did a lot of work to try and get the right answer, so Im not putting that work to waste

8 0

3 years ago

Two sides of a triangle measure 9 cm and 23 cm what could be the measurement of the third side of the triangle

Vladimir79 [104]

Pythagorean Theorem: a^2+b^2=c^2
(9)^2 + b^2 = (23)^2
81 + b^2 = 529
b^2 = 529 - 81
b^2 = 448
b^2 =
$\sqrt{448}$
b = 21.2

6 0

2 years ago

Simplify this expression: 1/2(10x + 12) - (3.5x - 7) *

Anna71 [15]

Simplified Expression:

1.5x+13

7 0

3 years ago

What is the y-coordinate of the midpoint of the line segment of (-4,13) and (18,-3.5)

Nady [450]

The midpoint is (7,4.75) so the y-coordinate should be y=4.75. I hope that helps

4 0

3 years ago

Ron's recycle shop had an old paper-shredding machine. Business was good, so he bought a new paper-shredding machine. The old ma

levacccp [35]

Answer: 1 hour 20 minutes

Step-by-step explanation:

Given : The old machine could shred a truckload of paper in 4 hours.

Rate of work done by old machine = $\dfrac{1}{4}$

The new machine could shred the same truckload in 2 hours.

Rate of work done by new machine = $\dfrac{1}{2}$

Let 't' be the time taken by both of them working together , then we have the following equation:-

$\dfrac{1}{t}=\dfrac{1}{4}+\dfrac{1}{2}\\\\\Rightarrow\dfrac{1}{t}=\dfrac{1+2}{4}\\\\\Rightarrow\dfrac{1}{t}=\dfrac{3}{4}\\\\\Rightarrow t=\dfrac{4}{3}=1\dfrac{1}{3}\ \text{ hours}$

Since 1 hour = 60 minutes

Then, $\dfrac{1}{3}\ \text{ hours}=\dfrac{1}{3}\times60=20\text{ minutes}$

Hence, it will take 1 hour 20 minutes to shred the same truckload of paper if Ron runs both shredders at the same time.

8 0

3 years ago