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2 years ago

6

Which of the following is equivalent to x^5 y^2/xy^2 when x=0 y=0

2 answers:

mafiozo [28]2 years ago

5 0

D is the correct answer

barxatty [35]2 years ago

3 0

The correct answer would be D because x = 0 so it would just be x and y is 2 and theres 2 y's so it would be 2+2 and thats 4 so take the x^4 power.

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Factors of 6:factors of 7:

Olenka [21]

6: 1,3,2,6
7: 1,7
Factors of 6 are 1,3,2,6 because 1x6 (6x1) and 3x2. (2x3)

Factors of 7 are 1,7 because seven is a odd number so you can only multiply it by one and itself. (1x7 or 7x1)

6 0

2 years ago

I-ready testing need help ASAP!

Leto [7]

Answer:

-11/12

Step-by-step explanation:

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2 years ago

Needed help for my math please

vesna_86 [32]

Answer:

see explanation

Step-by-step explanation:

(a)

$\frac{a}{a}$ = 1 ( any value divided by itself = 1 )

(b)

$\frac{a}{1}$ = a ( any value divide by 1 is the value itself )

(c)

$\frac{a}{b}$ × $\frac{c}{d}$ = $\frac{ac}{bd}$

The product of 2 fractions is the product of the numerators divided by the product of the denominators

(d)

$\frac{a}{b}$ ÷ $\frac{c}{d}$ = $\frac{ad}{bc}$

To divide 2 fractions, leave the first fraction, change division to multiplication and turn the second fraction upside down, that is

$\frac{a}{b}$ ÷ $\frac{c}{d}$ = $\frac{a}{b}$ × $\frac{d}{c}$ = $\frac{ad}{bc}$

(e)

$\frac{a}{d}$ + $\frac{b}{d}$ = $\frac{a+b}{d}$

Since the fractions have a like denominator, add the numerators leaving the denominator. This applies to subtraction also

(f)

$\frac{a}{d}$ - $\frac{b}{d}$ = $\frac{a-b}{d}$

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6 0

3 years ago

Let f(x) = tan(x) - 2/x. Let g(x) = x^2 + 8. What is f(x)*g(y)?

Tema [17]

Answer:

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

Step-by-step explanation:

We are given that

$f(x)=tan(x)-\frac{2}{x}$

$g(x)=x^2+8$

We have to find $f(x)\times g(y)$

To find the value of $f(x)\times g(y)$ we will multiply f(x) by g(y)

$g(y)=y^2+8$

Now,

$f(x)\times g(y)=(tanx-\frac{2}{x})(y^2+8)$

$f(x)\times g(y)=tan(x)(y^2+8)-\frac{2}{x}(y^2+8)$

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

Hence,

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

5 0

2 years ago

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SashulF [63]

Misha would combine 3x-2x and-8-7

5 0

3 years ago

Read 2 more answers