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Trava [24]
4 years ago
10

What is the value of 5 in 756

Mathematics
1 answer:
Anettt [7]4 years ago
7 0
The value of the 5 in 756 is 50
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How do you do this math
Basile [38]

Answer: y = -3x - 6

Step-by-step explanation:

One way to write a <u>linear equation</u> is with slope-intercept form.               Slope-intercept form is y = mx + b, where m is the slope, and b is the              y-intercept.

Thus, the equation is y = -3x - 6

Hope it helps :) and let me know if you are confused anywhere.

8 0
3 years ago
Read 2 more answers
NEED HELP WITH 21 PLZ HELP!?!!!????!
Rama09 [41]

Answer:

Hours

Step-by-step explanation:

21a. One week is too long so using hours will help, but when doing a quick thing you can use seconds.

21b. (Sorry I can't see the question, so I can't answer that part.)

:)

7 0
4 years ago
Orange 20 40 60
ElenaW [278]
Number of medium cherry slices : 10
number of medium orange slices : 40

ratio of cherry to orange : 10/40 reduces to 1/4 or 1:4 or 1 to 4
7 0
3 years ago
Read 2 more answers
A college entrance exam company determined that a score of 2222 on the mathematics portion of the exam suggests that a student i
kolbaska11 [484]

Answer:

Yes, Students are scoring above 2222 on the math portion of the​ exam.

Step-by-step explanation:

We are given that a college entrance exam company determined that a score of 2222 on the mathematics portion of the exam suggests that a student is ready for​ college-level mathematics i.e., population mean is 22.

Null Hypothesis, H_0 : \mu = 22 {Students are scoring equal to 2222 on the math portion of the​ exam}

Alternate Hypothesis, H_0 : \mu > 22 {Students are scoring above 2222 on the math portion of the​ exam}

Also, a random sample of 150 students who completed this core set of courses results in a mean math score of 22.7 on the college entrance exam with a standard deviation of 3.93 i.e.;

Sample mean, Xbar = 22.7    and Sample standard deviation, s = 3.93

The Test statistics is given by;

                            Z = \frac{Xbar -\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

Test Statistics = \frac{22.7 -22}{\frac{3.93}{\sqrt{150} } } ~ t_1_4_9

                        = 2.1815

Since, we are not given with the significance level, so we assume it to be 5%. At 5% significance level t table gives critical value of 1.6578 at 149 degree of freedom. Since our test statistics is more than the critical value so we reject null hypothesis as our test statistics fall in the rejection region.

Therefore, we conclude that Students are scoring above 2222 on the math portion of the​ exam.

7 0
3 years ago
In a fruit punch drink, the 3 ingredients are apple juice, orange juice and
slega [8]

Answer:

11/20

Step-by-step explanation:

ratio of cranberry juice is

1- 1/4 - 1/5

= 11/20

6 0
3 years ago
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