The triangles are congruent by SAS, so the two angles with 7x and 3x+16 are equal. So
7x=3x+16
4x=16
x=4
So KJL=7(4)=28.
For a line to be parallel, it must have the same slope as the first line so the slope of a parallel line would be -6.
Answer:
(5a - [2b - 7c]) and (5a + [2b + 7c])
Step-by-step explanation:
Factor 25a^2 - 4b^2 + 28bc - 49c^2.
Note that - 4b^2 + 28bc - 49c^2 involves the variables b and c, whereas 25a^2 has only one variable. Thus, try to rewrite - 4b^2 + 28bc - 49c^2 as the square of a binomial:
- 4b^2 + 28bc - 49c^2 = -(4b^2 - 28bc + 49c^2), or
-(2b - 7c)^2.
Thus, the original 25a^2 - 4b^2 + 28bc - 49c^2 looks like:
[5a]^2 - [2b - 7c]^2
Recall that a^2 - b^2 is a special product, the product of (a + b) and (a - b). Applying this pattern to the problem at hand, we conclude:
Thus, [5a]^2 - [2b - 7c]^2 has the factors (5a - [2b - 7c]) and (5a + [2b + 7c])
To solve the question, use the equation y=mx+b. Since you already know the slope (m), all you need is to find the b. Plug in the x and y from the point (9,2) and m:
2=3(9)+b
2=27+b (subtract 27 on both sides)
b=-25
The equation is y=3x-25
