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3 years ago

Convert 86,000 cm to km. Show all of your work

1 answer:

7 0

86,000cm
To convert cm to metres you will need to divide it by 100.
So, 86,000/ 100 which is equal to 860m
Then, to convert it to km, you need to divide your answer by 1000
So, 860m / 1000 is equal to 0.86km
Thus the answer is 0.86km

Hope this helped

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An airplane is traveling at an altitude of 30,000 feet

Murljashka [212]

Answer:

10 minutes

Step-by-step explanation:

First, find how much higher the airplane has to travel:

35,000 - 30,000

= 5,000

To fine how long it will take, divide 5000 by 500

5000/500

= 10

So, it will take 10 minutes to get above 35,000 feet

5 0

3 years ago

PLS HELP

Sloan [31]

Answer:

8√5 units.

Step-by-step explanation:

See the diagram in the coordinate plane attached.

A rhombus has four equal sides and to find the perimeter of the rhombus we have to measure any of the sides of the figure of the rhombus.

The coordinates of the topmost point are (-1,-1) and that of the rightmost point are (3,-3).

Therefore, side length of the rhombus will be

$\sqrt{(- 1 - 3)^{2} + (- 1 - (- 3))^{2}} = \sqrt{20} = 2\sqrt{5}$ units.

So, the perimeter of the rhombus will be (4 × 2√5) units = 8√5 units. (Answer)

The distance between two points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ on a coordinate plane is given by

$\sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2}}$

5 0

3 years ago

9. Write quadratic function with zeros 3, 6

Dmitry_Shevchenko [17]

Answer:

(x-3)(x-6)

Step-by-step explanation:

do you want an explanation?

7 0

3 years ago

Please help me ill mark brainlyest if correct

Eva8 [605]

Answer:

50m²

Explanation:

first, we have to find the length and width of the backyard. since 4cm represents 5m, we know that the real width of the backyard is 5m.

as for the length of the backyard, 8cm is double of 4cm so we can also double 5m to get 10m.

now, we can find the area by taking 5m × 10m = <u>50m²</u>.

i hope this helps! :D

7 0

3 years ago

Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. (a) Descri

OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

$\mu = 74$

and

$\sigma = 6$

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

$\mu = 74$

The standard error of the means becomes the standard deviation of the sampling distribution.

$\sigma_ { \bar X } = \frac{ \sigma}{ \sqrt{n} } \\ \sigma_ { \bar X } = \frac{ 6}{ \sqrt{36} } = 1$

Part b) We want to find

$P(\bar X \:>\:75.9)$

We need to convert to z-score.

$P(\bar X \:>\:75.9) = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: 1.9) \\ = 0.0287$

Part c)

We want to find

$P(\bar X \: < \:71.95)$

We convert to z-score and use the normal distribution table to find the corresponding area.

$P(\bar X \: < \:71.95) = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: - 2.05) \\ = 0.0202$

Part d)

We want to find :

$P(73\:$

We convert to z-scores and again use the standard normal distribution table.

$P( \frac{73 - 74}{1} \:< \: z$

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3 years ago