All categories

3 years ago

What is the length of the diagonal of a rectangle that is 18 feet long by 15 feet wide

Mathematics

1 answer:

Tresset [83]3 years ago

6 0

Answer:

the answer is 23.431 feet.

Step-by-step explanation:

you divide the rectangle with the diagonals and you obtain a right angled triangle whose base is 18 feet and height 15 feet. The hypotenuse of the right angled triangle is the diagonal of the rectangle. SO using the <u><em>pythagoras</em></u> theorem you find the length of the hypotenuse.

$\sqrt18^2 + 15^2\\=\sqrt 549\\=23.431$

You might be interested in

At a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. T

klio [65]

The formula for finding area of a circle is $\pi r^2$ .

Essentially, we have two circles here. One is a larger outer circle, and the other in a smaller inner circle. In order to find the area of the sidewalk, we must find the area of the outer circle, then find the are of the inner circle. After we find both areas, we subtract.

See attached image for process of finding area, and subtracting areas to find the final area of the sidewalk.

4 0

3 years ago

A Treasure hunt competition has eliminations each round. The table below shows the number of players in each of the first 5 roun

vovikov84 [41]

I think its c if i did it right

5 0

3 years ago

Please help, Pre-Algebra super easy math question

ivanzaharov [21]

Answer:

-16

Step-by-step explanation:

b) -x²; x = -4

-(-4)²

-(16)

-16

I hope this helps!

7 0

2 years ago

Read 2 more answers

A car tracked 649 miles at a certain speed. If the speed of had been 8 mph faster, the trip could have been made in 4 hours less

Mkey [24]

Answer:

Step-by-step explanation:

let s be speed and t be time taken

s*t=649

(s+8)(t-4)=649

st-4s+8t-32=649

-4s+8t-32=0

4s=8t-32

s=2t-8

2t=s+8

t=4+s/2

$s*(\frac{s}{2}+4)=649\\s^2+8s=649\\s^2+8s-649=0\\find s$

7 0

4 years ago

HELP ASAP WILL REQARD BRAINLIEST

schepotkina [342]

Part A

1. 14k+k<30

Add the left hand side to get;

15k<30

Divide both sides by 15.

$\frac{15k}{15}\:$

k<2

2. We have 9d-3d+7>31

Group similar terms to obtain:

9d-3d>31-7

Combine similar terms:

6d>24

Divide both sides by 6

$\frac{6d}{6}\:>\:\frac{24}{6}$

This implies that:

d>4

3. We have 13x-2x>77

This implies:

11x>77 $\frac{11x}{11} \:>\:\frac{77}{11}$

x>7

4. We have 5y<7y+18

This implies

5y-7y<18

-2y<18

Divide both sides by -2 and reverse the sign.

$\frac{-2y}{-2} \:>\:\frac{18}{-2}$

$y\:>\:-9$

5. The given expression is;

3f-12>-10+9f

Group similar terms:

-12+10>9f-3f

-2>6f

Divide both sides by 6.

$\frac{-2}{6}\:>\:\frac{6f}{6}$

$-\frac{1}{3}\:>\:f$

$f\:$

6. We have 4t-8<2t-2

Group similar terms;

4t-2t<-2+8

2t<6

t<3

7. We have

15h+16>6h-20

Group like terms;

15h-6h>-20-16

9h>-36

Divide both sides by 9

h>-4

8. The given inequality is

4r-2r>6-r

This implies

4r-2r+r>6

3r>6

r>2

Part B

x-27=193

x=193+27

x=220

2. The given equation is

f(12)=48

12f=48

f=48/12

f=4

3. We have the equation 4s+2=74

4s=74-2

4s=72

s=18

4. The given equation is

9(r+1)-18=2r+12

Expand to get:

9r+9-18=2r+12

Group like terms:

9r-2r=12+18-9

7r=21

r=3

5 0

3 years ago