First we need to write the null and alternate hypothesis for this case.
Let x be the average number of text message sent. Then
Null hypothesis: x = 100
Alternate hypothesis: x > 100
The p value is 0.0853
If p value > significance level, then the null hypothesis is not rejected. If p value < significance level, then the null hypothesis is rejected.
If significance level is 10%(0.10), the p value will be less than 0.10 and we reject the null hypothesis and CAN conclude that:
The mean number of text messages sent yesterday was greater than 100.
If significance level is 5%(0.05), the p value will be greater than 0.05 and we cannot reject the null hypothesis and CANNOT conclude that:
The mean number of text messages sent yesterday was greater than 100.
X+7-3=1
X+4=1
-4 -4
X=-3
Copy exactly how you see it
Answer:
Presumably you're solving for x here? Without further information we'll assume that.
With that in mind, x is approximately equal to 0.86 and -0.46
Step-by-step explanation:
Let's start by putting it in the usual ax² + bx + c format.
let's solve it. First we'll multiply both sides by five, making the first term a perfect square:
Now we'll add 11 to both sides:
Which makes the left side a perfect square:
And now we can solve for x:
Note that there's no apparent way of drawing the ± symbol when editing equations, so take that + sign as actually being ±.
That gives us two answers:
He bought 4 books.
3.95m + 8.95b = 47.65
If he bought 3 magazines, m =3
(3.95)3 +8.95b = 47.65
11.85 + 8.95b =47.65
now we subtract 11.85 from both sides
8.95b = 35.80
we divide both sides by 8.95
b=4
Hugh bought 4 books.
Subtract what has already been loaded from total amount allowed:
23500 - 9700 = 13,800
Divide the amount left by the weight of each crate:
13,800 / 70 = 197.14
They can load 197 crates.
