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masya89 [10]
3 years ago
15

The system ax-by=-16 and ax+2y=20 has one solution at the point (3,4). Find a and b. (a=4,b=7)

Mathematics
1 answer:
RSB [31]3 years ago
8 0

Answer:

Step-by-step explanation:

substitute (3,4) to equation: ax+2y=20

3a+8=20

a=4

Then, 4x-by=-16

substitute (3,4) to solve b,

4*3-b(4)=-16

b=7

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Find the simple interest and amount when principal = Rs. 6000, rate = 6% per annum and time = 4 years
Alinara [238K]

Given:

Principal = Rs. 6000

Rate of simple interest = 6% per annum.

Time = 4 years

To find:

The simple interest and amount.

Solution:

Formula for simple interest:

I=\dfrac{P\times r\times t}{100}

Where, P is principal, r is the rate of interest and t is the number of years.

Putting P=6000, r=6 and t=4, we get

I=\dfrac{6000\times 6\times 4}{100}

I=60\times 6\times 4

I=1440

Now,

Amount=Principal+Interest

Amount=6000+1440

Amount=7440

Therefore, the simple interest is Rs. 7440 and the amount is Rs 7440.

7 0
3 years ago
is (-1/2 x + 6/7) - (7/2 x - 4/7) equivalent to -4 x + 2/7 ? use the properties of operations to justify your answer
LuckyWell [14K]

Answer:

The given equation is NOT justified.

Step-by-step explanation:

Here, the given equation is (\frac{-1}{2}x + \frac{6}{7} )  -  (\frac{7}{2}x - \frac{4}{7} )   = -4x + \frac{2}{7}

Now, here Consider the left hand side and simplifying the left side by operating on the like terms,

⇒(\frac{-1}{2}x + \frac{6}{7} )  -  (\frac{7}{2}x - \frac{4}{7} )   = \frac{-1}{2}x + \frac{6}{7}   -  \frac{7}{2}x + \frac{4}{7}  =  (\frac{-1}{2}x -\frac{7}{2}x) + (\frac{6}{7}   + \frac{4}{7})

=(\frac{-1 - 7}{2}x ) + (\frac{6 + 4}{7} ) = \frac{-8x}{2} + \frac{10}{7}   \neq -4x + \frac{2}{7}

Here, Left side of equation  ≠ Right side of the equation

Hence, (\frac{-1}{2}x + \frac{6}{7} )  -  (\frac{7}{2}x - \frac{4}{7} )   ≠ -4x + \frac{2}{7}

4 0
3 years ago
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