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Natasha_Volkova [10]
3 years ago
10

Please help with 2 and 3 for maths

Mathematics
2 answers:
Vera_Pavlovna [14]3 years ago
8 0

Answer:2-4=

Step-by-step explanation:y-16-(-42)

y-16+16

y-32

y-16-(-22)

y-16+4

y-20

y-16-(02)

y-16

y-16-(42)

y-0

AnnyKZ [126]3 years ago
6 0

Answer:

The answer is 2-4

Step-by-step explanation:

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Someone please answer this for me
Alenkinab [10]

Diameter 4m, radius is half,

Radius Answer: 2  m

Volume is

V = (4/3)πr³ = (4/3)π 2³ = (4/3)π(8) = (32/3) π

Answer: 32/3            (× π cubic meters)

4 0
3 years ago
Solve: 2 in 3= in (x-4)<br> A: x=9<br> B: x=10<br> C: x=13
Margaret [11]

Answer:

x = 13

Step-by-step explanation:

Please use " ln " for the "natural logarithm," not " in. "

Then you have:    2 ln 3= ln (x-4)

We need to get rid of the " ln " operator.  Rewrite 2 ln 3 as ln 3² = ln (x - 4).

Then 3² = x - 4, or 9 = x - 4, or  x = 13

8 0
4 years ago
Read 2 more answers
Please help the one i used red marker to cross out dont do it. tyy
Temka [501]
579, that is it! okay
4 0
3 years ago
Read 2 more answers
A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and
IRINA_888 [86]

Answer:

<em>The approximate percentage of cars that remain in service between 73 and 84 months</em>

<em>P( 73 < x < 84 ) = 0.02145 = 2.1 %</em>

<u>Step-by-step explanation</u>:

<u><em>Explanation</em></u>:-

Given mean of the Population 'μ ' = 51 months

Standard deviation of the Population 'σ' = 11 months

Let 'X' be the random variable of Normal distribution

<em>Let    'X'  = 73</em>

<em></em>Z = \frac{x-mean}{S.D} = \frac{73-51}{11} = 2<em></em>

<em>Let  'X' = 84</em>

<em></em>Z = \frac{84-51}{11} = 3<em></em>

<em>The approximate percentage of cars that remain in service between 73 and 84 months</em>

<em>P( 73 < x < 84 )      = P( 2 < Z < 3)</em>

<em>                               = P( Z<3) - P( Z <2)</em>

<em>                              =  0.5 + A(3) - ( 0.5 + A(2))</em>

<em>                             = A(3) - A( 2)</em>

<em>                             = 0.49865 - 0.4772     ( From Normal table)</em>

<em>                             = 0.02145</em>

<em>  P( 73 < x < 84 ) = 0.02145</em>

<em>The approximate percentage of cars that remain in service between 73 and 84 months</em>

<em>P( 73 < x < 84 ) = 0.02145 = 2.1 %</em>

7 0
3 years ago
The researcher trains a sample of 16 individuals in mindfulness and then collects data on how long they spend eating per day. Th
Mila [183]

Answer:

The calculated t-value is t=0.47.

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>"Americans typically eat quickly and do not spend time enjoying their meal. A researcher plans to test if those trained in mindfulness will take more time to enjoy their meal (that is, they will spend more time eating than the general population). The general population spends an average of 68 minutes per day combined eating their three meals. The researcher trains a sample of 16 individuals in mindfulness and then collects data on how long they spend eating per day. The sample mean for those trained in mindfulness equals 74; the SS = 150. What is the calculated t-value? Round your answer to two decimal places."</em>

The degrees of freedom are (n-1)=(16-1)=15

The standard deviation is:

s=\sqrt{\frac{SS}{n-1}}=\sqrt{\frac{150}{16-1}}=\sqrt{10}=3.16

The t-value can be calculated as:

t=\frac{M-\mu}{\sigma/\sqrt{n}} =\frac{74-68}{3.16/\sqrt{16}} \\\\t=\frac{6}{3.16*4}=\frac{6}{12.64}= 0.47

4 0
3 years ago
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