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➷ Perpendicular ==> negative reciprocal slope
1 = (-1/3)(3) + c
1 = -1 + c
c = 2
It would be y = -1/3x + 2
Q3) slope = difference in y / difference in x
Eq 1 slope: 1/3
Eq 2 slope: -1/3
Eq 3 slope: 1/3
Eq 4 slope: 3/1
It would be The line passing through points (1,4) and (4.3)
A line is perpendicular if it has the negative reciprocal slope
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Very simple. You just use the vectors as normal numbers, and multiply the coordinates with 2 and 4 like this:
2*u = 2* (2,4) = (4,8)
4*w = 4* (-1,3) = (-4,12)
(4,8) - (-4,12) = (8,-4)
So the vector has the coordinates (8,-4)
Answer:10.5
Step-by-step explanation:You just add 1.75 6 times.
Answer:
4
Step-by-step explanation:
2x+y=12
y=-2x+12
y-2=3(x-2)
If it’s parallel to each other: the slope has to be the same.
If is perpendicular to each other: the slope should be the reciprocal to each other.
The first equation has a slope of -2
The second has a slope of 3
Neither the condition meet. So the answer is 4