There are white, blue, and red boats in a marina. Two-thirds of the boats in the marina are white, five-eighths of the remaining
boats are blue, and the rest are red. If there are 6 red boats, how many boats are in the marina?
1 answer:
X = total boats
2/3x are white....so the remaining boats = 1/3x
5/8 of the remaining boats are blue.....5/8 * 1/3 = 5/24x are blue
2/3 + 5/24 = 16/24 + 5/24 = 21/24 are blue and white......so 3/24 are red
3/24x = 6
x = 6 * 24/3
x = 144/3
x = 48 total boats in the marina <==
2/3(48) = 32 white
5/24(48) = 10 blue
3/24(48) = 6 red
You might be interested in
Answer:
12
Step-by-step explanation:
3x + y = 6
Multiply both sides by 2
6x + 2y = 12
a) For x = 27:
z = 27-28/2 = -0.5
For x = 31:
z = 31-38/2 = 1.5
From the normal distribution table, P(27 < x < 31) = P(-0.5 < z < 1.5) = P(z < 1.5) - P(z < -0.5) = 0.9332 - 0.3085 = 62.47%
b) For x > 30.2:
z = 30.2-28/2 = 1.1
From the normal distribution table, P(x > 30.2) = P(z > 1.1) = 1 - P(z > 1.1) = 1 - 0.8643 = 13.57%
Answer:
1. Communative Property
2. Associative Property
3. Zero Property
Step-by-step explanation:
Answer:
-146.03008
Step-by-step explanation:
(-8.149)(17.92) = -146.03008
Answer:
-9
Step-by-step explanation:
set y to 0
-2x + 1/2y = 18
-2x +1/2(0)=18
-2x / -2 = 18 /-2
x = -9
