The sign of f on the interval -7/3 < x < -3/5 is always positive.
<h3>How to solve for the sign on the interval</h3>
We have the equation
(5x+3)(x−2)(3x+7)(x+5) > 0
Now when f(x) > 0
Then -7/3 < x < -3/5
This would tell us that the sign would become positive when it changes from the less than to greater than sign
<h3>Complete Question</h3>
f(x)=(5x+3)(x-2)(3x+7)(x+5) has zeros at x=-5, x=-7/3, x=-3/5, and x=2
What is the sign of f on the interval -7/3<x<-3/5?
answer choices
f is always positive on the interval
f is always negative on the interval
f is sometimes positive and sometimes negative on the interval
f is never positive or negative on the interval
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Answer:
you can't find the square root of a negative
Step-by-step explanation:
Answer:
x/8
Step-by-step explanation:
First, we are given "the quotient of...". This means that we are dividing something/something else. If two numbers are given in the phrase "something and something else", the first number given will be the something, and the second number will be the something else.
The first number listed is x. Therefore, we have
x/something else.
Next, we are given "and 8", so we have x/8 as our expression
Step-by-step explanation:
cos F = HF/FG
cos 52° = x/(4.3)
0.6 = x/4.3
=> x = 4.3 × 0.6
x = 2.58
so the length of HF = 2.58 = 2.6 ft
Answer:
6
Step-by-step explanation:
Since 3/4 has a different denominator then 1/8 we can multiply 3/4 by 2 to get 6/8 which has the same denominator. Now we just divide the numerators and denominators by each other to get 6.
