76 82 87 93 95 98
Mean -
76+82+87+93+95+98 = 531
531/6 = 88.5
Range -
98 - 76 = 22
Median -
Because there are 6 numbers you have to find the average of the middle two
87+93 = 180
180/2 = 90
Mode -
No number is repeated so there is no mode.
Domain: {-4,0,8}
Range: {1,5,10}
The answer is true to all of them.
Answer: 0.9104
Step-by-step explanation:
Given : A hardware store receives a shipment of bolts that are supposed to be 12 cm long.
Mean : 
Standard deviation : 
Sample size : n=10
Since, they will declare the shipment defective and return it to the manufacturer if the average length of the 100 bolts is less than 11.97 cm or greater than 12.04 cm.
So for the shipment to be satisfactory, the length of the bolts must be between 11.97 cm and 12.04 cm.
We assume that the length of the bolts are normally distributed.
Let X be the random variable that represents the length of randomly picked bolt .
For Z score : 
For x = 11.97

For x = 12.04

By using the standard normal distribution table , the probability that the shipment is found satisfactory will be :-

Hence, the probability that the shipment is found satisfactory=0.9104
As an estimate the sum may read 720-210, which makes 510