well, we know that θ is in the III Quadrant, where the sine is negative and the cosine is negative as well, or if you wish, where "x" as well as "y" are both negative, now, the hypotenuse or radius of the circle is just a distance amount, so is never negative, so in the equation of cos(θ) = - (2/5), the negative must be the adjacent side, thus


Plug in 3 for x so
2(3)+2
6+2=
8
The evaluation is 8
Expanding the digits, we have

X has to be higher than 1. 5-3 is 2, which is equal to two but not greater than. X cannot be less than 1. To show this in an inequality:
x

1