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3 years ago

Use the Distributive Property to expand this expression. z(–6.4 – 3.5x)

Mathematics

1 answer:

dedylja [7]3 years ago

3 0

Answer:

$z\left(-6.4\:-3.5x\right)=-6.4z-3.5zx$

Hence, Option 'C' is true.

Step-by-step explanation:

Given the expression

$z\left(-6.4\:-3.5x\right)$

Apply distributive law: $a\left(b-c\right)=ab-ac$

Here: $a=z,\:b=-6.4,\:c=3.5x$

so the expression becomes

$z\left(-6.4\:-3.5x\right)=z\left(-6.4\right)-z\cdot \:\:3.5x$

$=-6.4z-3.5zx$ ∵ $+\left(-a\right)=-a$

Therefore,

$z\left(-6.4\:-3.5x\right)=-6.4z-3.5zx$

Hence, option 'C' is true.

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3 years ago

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3 years ago

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MrRa [10]

Answer:

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Step-by-step explanation:

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3 years ago

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assume that when adults with smartphones are randomly selected 15 use them in meetings or classes if 15 adult smartphones are ra

Tanzania [10]

Answer:

The probability that at least 4 of them use their smartphones is 0.1773.

Step-by-step explanation:

We are given that when adults with smartphones are randomly selected 15% use them in meetings or classes.

Also, 15 adult smartphones are randomly selected.

Let X = Number of adults who use their smartphones

The above situation can be represented through the binomial distribution;

$P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; n = 0,1,2,3,.......$

where, n = number of trials (samples) taken = 15 adult smartphones

r = number of success = at least 4

p = probability of success which in our question is the % of adults

who use them in meetings or classes, i.e. 15%.

So, X ~ Binom(n = 15, p = 0.15)

Now, the probability that at least 4 of them use their smartphones is given by = P(X $\geq$ 4)

P(X $\geq$ 4) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

= $1- \binom{15}{0}\times 0.15^{0} \times (1-0.15)^{15-0}-\binom{15}{1}\times 0.15^{1} \times (1-0.15)^{15-1}-\binom{15}{2}\times 0.15^{2} \times (1-0.15)^{15-2}-\binom{15}{3}\times 0.15^{3} \times (1-0.15)^{15-3}$

= $1- (1\times 1\times 0.85^{15})-(15\times 0.15^{1} \times 0.85^{14})-(105 \times 0.15^{2} \times 0.85^{13})-(455 \times 0.15^{3} \times 0.85^{12})$

= 0.1773

3 0

3 years ago

Solve 0.06*0.7+0.03=0.06*(-0.2)+0.03

larisa86 [58]

Answer 0.06*0.7+0.03=0.072 and 0.06*(-0.2)+0.03=0.018

6 0

3 years ago