If you would like to solve (2x - 6) * (3x^2 - 3x - 6), you can do this using the following steps:
(2x - 6) * (3x^2 - 3x - 6<span>) = 2x * 3x^2 - 2x * 3x - 2x * 6 - 6 * 3x^2 + 6 * 3x + 6 * 6 = 6x^3 - 6x^2 - 12x - 18x^2 + 18x + 36 = 6x^3 - 24x^2 + 6x + 36
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The correct result would be <span>6x^3 - 24x^2 + 6x + 36.</span>
Ok,
The total is 63$:
= 63
It shows us one of the numbers for the equation, 13
+ 13 = 63
Two passes together plus the thirteen equals the total of 63$
the price of the pass is unknown, so we can use a variable to figure it out:
2x + 13 = 63
Now we solve
First subtract 13 from both sides:
2x + 13 - 13 = 63 - 13
Then divide both sides by 2:
2x ÷ 2 = 50 ÷ 2
Now we get our answer:
x = 25
Answer:
7 5/12
Step-by-step explanation:
5 1/4 + 3/4 + 1 5/12
We can add the first two terms
5 1/4 + 3/4
5 4/4
6
6 + 1 5/12
7 5/12
Answer:
the solution is (3,4) (the second one)
Step-by-step explanation:
