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olchik [2.2K]
3 years ago
10

16x^4-24x^3+20/-4x need help on this problem

Mathematics
1 answer:
Mama L [17]3 years ago
6 0
Assuming ya mean
\frac{16x^4-24x^3+20}{-4x}
remember
\frac{a+b}{c}=\frac{a}{c}+\frac{b}{c}
and
\frac{x^m}{x^n}=x^{m-n}

so
\frac{16x^4-24x^3+20}{-4x}=
\frac{16x^4}{-4x}+\frac{-24x^3}{-4x}+\frac{20}{-4x}=
-4x^3+6x^2+\frac{-5}{x}=
-4x^3+6x^2-\frac{5}{x}
that's the best I can do
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