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Helga [31]
3 years ago
9

Find the distance between the points (5,-3) and (0,2).

Mathematics
2 answers:
alina1380 [7]3 years ago
8 0

Answer:

A

Step-by-step explanation:

Calculate the distance (d) using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (5, - 3) and (x₂, y₂ ) = (0, 2)

d = \sqrt{(0-5)^2+(2+3)^2}

  = \sqrt{(-5)^2+5^2}

  = \sqrt{25+25}

  = \sqrt{50} = \sqrt{25(2)} = 5\sqrt{2}

wolverine [178]3 years ago
3 0

Answer:

option a

Step-by-step explanation:

we have the equation of distance between two points :

d=\sqrt{(x2-x1)^2+(y2-y1)^2}

first point (5,-3)

second point (0,2)

so we have

d=\sqrt{(0-5)^2+(2-(-3))^2}

d=\sqrt{25+25}

d=\sqrt{50}

50=(5^2)*2

so we have d=\sqrt{50} = \sqrt{5^2*2

d=5\sqrt{2}

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Answer:

5

Step-by-step explanation:

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3 years ago
Suppose PR = 54, solve for QR<br> 4x-1<br> 3x-1<br> P<br> R
Svet_ta [14]

Answer:

QR = 23

Step-by-step explanation:

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5 0
4 years ago
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stich3 [128]
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8 0
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Seven times a number is less than or equal to a quantity that is 24 less than that same
Ad libitum [116K]

Answer:

7x\leq x-24

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Step-by-step explanation:

Let x denotes the required number that satisfies the following condition.

''seven times a number is less than or equal to a quantity that is 24 less than that same  number''

Seven times a number is equal to 7x

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Now find the inequality.

As seven times a number is less than or equal to a quantity that is 24 less than that same  number,

7x\leq x-24

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