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Helga [31]
3 years ago
9

Find the distance between the points (5,-3) and (0,2).

Mathematics
2 answers:
alina1380 [7]3 years ago
8 0

Answer:

A

Step-by-step explanation:

Calculate the distance (d) using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (5, - 3) and (x₂, y₂ ) = (0, 2)

d = \sqrt{(0-5)^2+(2+3)^2}

  = \sqrt{(-5)^2+5^2}

  = \sqrt{25+25}

  = \sqrt{50} = \sqrt{25(2)} = 5\sqrt{2}

wolverine [178]3 years ago
3 0

Answer:

option a

Step-by-step explanation:

we have the equation of distance between two points :

d=\sqrt{(x2-x1)^2+(y2-y1)^2}

first point (5,-3)

second point (0,2)

so we have

d=\sqrt{(0-5)^2+(2-(-3))^2}

d=\sqrt{25+25}

d=\sqrt{50}

50=(5^2)*2

so we have d=\sqrt{50} = \sqrt{5^2*2

d=5\sqrt{2}

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Answer:

It takes 1 seconds for push-ups and 3 seconds for sit-ups for Mei to do exercise.

Step-by-step explanation:

Given:

Let the time taken for push-ups be 'x'.

Let the time taken for sit-ups be 'y'.

Now Given:

17 push-ups and 6 sit-ups, it takes a total of 35 seconds.

So we can say that;

17x+6y=35 \ \ \ \ equation \ 1

Also Given:

41 seconds to do 20 push-ups and 7 sit-ups.

so we can say that;

20x+7y=41 \ \ \ \ equation \ 2

Now Multiplying equation 1 by 7 we get;

7(17x+6y)=35\times7\\\\119x+42y= 245 \ \ \ \ equation \ 3

Now Multiplying equation 2 by 6 we get;

6(20x+7y)=41\times6\\\\120x+42y = 246 \ \ \ \ equation\ 4

Now Subtracting equation 3 from equation 4 we get;

120x+42y-(119x+42y)=246-245\\\\120x+42y-119x-42y=1\\\\x=1\ sec

Now substituting the value of x in equation 1 we get;

17x+6y=35\\\\17\times1+6y=35\\\\17+6y=35\\\\6y=35-17\\\\6y= 18\\\\y=\frac{18}6 = 3\ seconds

Hence It takes 1 seconds for push-ups and 3 seconds for sit-ups for Mei to do exercise.

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Marta_Voda [28]

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Step-by-step explanation:

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What is the equation of the axis of symmetry for this function? H(x) = -X2 + 10x - 11 x = -5 0 x= -10 x = 5 x = 10
siniylev [52]

Given:

The equation of a quadratic function is:

H(x)=-x^2+10x-11

To find:

The equation of the axis of symmetry for the given function.

Solution:

If a quadratic function is f(x)=ax^2+bx+c, then the equation of the axis of symmetry is:

x=-\dfrac{b}{2a}        ...(i)

We have,

H(x)=-x^2+10x-11

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3 years ago
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