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alisha [4.7K]
3 years ago
11

Math Question Please Help

Mathematics
1 answer:
Katena32 [7]3 years ago
5 0
You just add 16. The answer is 32.<span />
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Triangle ABC
Stolb23 [73]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Let's solve for value of values of x and y ~

According to Angle sum property of triangles :

\qquad \sf  \dashrightarrow \: 70 \degree + 58\degree + x = 180\degree

\qquad \sf  \dashrightarrow \: x\degree + 128\degree = 180\degree

\qquad \sf  \dashrightarrow \:x =  180\degree - 128\degree

\qquad \sf  \dashrightarrow \: x = 52\degree

Now, solve for y ~

\qquad \sf  \dashrightarrow \: 70\degree + 49\degree + y = 180\degree

\qquad \sf  \dashrightarrow \:  y + 119 = 180\degree

\qquad \sf  \dashrightarrow \:  y =  180  -  119\degree

\qquad \sf  \dashrightarrow \:  y = 61 \degree

Now, by the results we got, we can conclude that :

The two triangles are not similar because 70 + 58 + x = 180 means x = 52° and 70 + 49 + y=180 means y = 61°

8 0
2 years ago
Read 2 more answers
A.)90<br> B.)41<br> C.)15<br> D.)83
Natalija [7]

Answer:

D

Step-by-step explanation:

∠ABC= ∠DBE (vert. opp. ∠s)

(6x -7)°= (4x +23)°

6x -7= 4x +23

<em>Being</em><em> </em><em>x</em><em> </em><em>terms</em><em> </em><em>to</em><em> </em><em>1</em><em> </em><em>side</em><em>,</em><em> </em><em>constant</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>other</em><em>:</em>

6x -4x= 23 +7

<em>Simplify</em><em>:</em>

2x= 30

<em>Divide</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>by</em><em> </em><em>2</em><em>:</em>

x= 15

<em>Substituting</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>x</em><em>:</em>

m∠ABC

= 6(15) -7

= 83

3 0
3 years ago
Exercise 2.4.2: Proving statements about rational numbers with direct proofs. About Prove each of the following statements using
IgorLugansk [536]

Answer:

See Explanation

Step-by-step explanation:

(a) Proof: Product of two rational numbers

Using direct proofs.

Let the two rational numbers be A and B.

Such that:

A = \frac{1}{2}

B = \frac{2}{3}

The product:

A * B = \frac{1}{2} * \frac{2}{3}

A * B = \frac{1}{1} * \frac{1}{3}

A * B = 1 * \frac{1}{3}

A * B = \frac{1}{3}

Proved, because 1/3 is rational

(b) Proof: Quotient of a rational number and a non-zero rational number

Using direct proofs.

Let the two rational numbers be A and B.

Such that:

A = \frac{1}{2}

B = \frac{2}{3}

The quotient:

A / B = \frac{1}{2} / \frac{2}{3}

Express as product

A / B = \frac{1}{2} / \frac{3}{2}

A / B = \frac{1*3}{2*2}

A / B = \frac{3}{4}

Proved, because 3/4 is rational

(c) x + y is rational (missing from the question)

Using direct proofs.

Let x and y be

Such that:

x = \frac{1}{2}

y = \frac{2}{3}

The sum:

x + y = \frac{1}{2} + \frac{2}{3}

Take LCM

x + y = \frac{3+4}{6}

x + y = \frac{7}{6}

Proved, because 7/6 is rational

<em>The above proof works for all values of A, B, x and y; as long as they are rational values</em>

8 0
3 years ago
What's the gcf of 47 and 17
ElenaW [278]

Answer:

The GCF of 47 and 17 is 1

Step-by-step explanation:

6 0
3 years ago
WILL GIVE BRAINLIEST<br> Subtract 9x^2+7x-2<br> from 8x-10
konstantin123 [22]

Answer:

x − 9 x ^2 − 8

Step-by-step explanation:

6 0
3 years ago
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