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3 years ago

Math Question Please Help

Mathematics

1 answer:

Katena32 [7]3 years ago

5 0

You just add 16. The answer is 32.<span />

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Braydon is performing the four arithmetic operations on 14 and 2.

Luda [366]

The answer is 14 divided by 2

4 0

3 years ago

Expand -8 to the 3rd power

BigorU [14]

Use a calculator lollll

8 0

3 years ago

A factory sells backpacks for $35 each. The cost to make 1 backpack is $15. In addition to the cost of making backpacks, the fac

Otrada [13]

Answer:9400 backpacks

$\geq$ Step-by-step explanation

since the number of packs to be sold in a is represented by x,

selling price for 1 week = 35x

cost price for 1 week = 15x

profit = 35x-15x = 20x

additional cost of production = 11,000

this implies that 20x - 11,000 $\geq$ 7800

20x - 11,000 $\geq$ 7,800

20x $\geq$ 7800+ 11000

20x $\geq$ 18,800

x $\geq$ 18800/2

x $\geq$ 9,400

at least 9,400 packs have to be sold each week to make a profit of $7800

7 0

3 years ago

At the circus, a clown is shot from a cannon. This situation can be modeled by the function: h = – 16t2 + 45t + 15, where 'h' is

weeeeeb [17]

Answer:

The maximum height is 46.64 feet.

Step-by-step explanation:

If we take the derivative of h whit respect to t and equal this to zero we would find the value of t which corresponds to the maximum h.

So, we have the function h(t):

$h(t)=-16t^{2} + 45t + 15$

Taking the derivative, we have:

$\frac{dh(t)}{dt}=-32t + 45=0$

Now, we solve it for t:

$t=\frac{45}{32}=1.4\: s$

Finally, we put this value of t into the original equation.

$h(t)=-16(1.4)^{2} + 45(1.4) + 15$

$h_{max}=46.64\: ft$

Therefore, the maximum height is 46.64 feet. All the given options are wrong, the one that comes closest is option A.

I hope it helps you!

4 0

2 years ago

How to solve this :') please help

blsea [12.9K]

Answer:

3/2

Step-by-step explanation:

sin(3π/4 - β) = sin(3π/4)cosβ - cos(3π/4)sinπ =

$\sin(\frac{3\pi}{4}-\beta)=\sin(\frac{3\pi}{4})\cos\beta-\cos\frac{3\pi}{4}\sin\beta\\=\frac{1}{\sqrt{2}}\cos\beta-(-\frac{1}{\sqrt{2}})\sin\beta\\\\=\frac{1}{\sqrt{2}}(\cos\beta +\sin\beta)\\\\\sin^2(\frac{3\pi}{4}-\beta)=\frac{1}{2}\cos\beta +\sin\beta)^2=\frac{1}{2}(\cos^2\beta +\sin^2\beta+2\sin\beta\cos\beta\\=\frac{1}{2}(1+\sin2\beta)=\frac{1}{2}(1-\frac{1}{5}) = \frac{2}{5}\\$

Use $\cot^2x=\csc^2x-1=\frac{1}{\sin^2x}-1$

$\cot^2(\frac{3\pi}{4}-\beta)=\frac{1}{\sin^2(\frac{3\pi}{4}-\beta)}-1 = \frac{1}{\frac{2}{5}}-1=\frac{5}{2}-1=\frac{3}{2}$

7 0

2 years ago