Shirley/Tracey has to stay at least 10 days for the M and N to cost less
The cross product of two vectors gives a third vector
that is orthogonal to the first two.
Normalize this vector by dividing it by its norm:
To get another vector orthogonal to the first two, you can just change the sign and use
.
Step 1: multiple the second equation by 2 so that you get -1/4 for the coefficient of y, the same as in equation 1
equation 2 multiply by 2: 1/4 x - 1/4 y=38 ..........name this equation 3
subtract equation 1 from equation 3: (1/4 x -1/2 x)=38-10
-1/4 x = 28
x=-112
plug in x=-112 in any of the equation, you will get y=-264
so the answer is A
Not necessarily. You could have done your multiplication wrong. Or in some cases, yes, you could have to use another skill. For example, you can't solve an optimization problem with addition, you need some calculus skills under your belt.
9514 1404 393
Answer:
y -2 = -2/3(x +4)
Step-by-step explanation:
There are several different forms of the equation for a line. Each is useful in its own way. Here, the line crosses the y-axis at a point between integer values, so using that intercept point could be problematical. That suggests the "point-slope" form of the equation for a line would be a better choice.
That form is ...
y -k = m(x -h) . . . . . . . line with slope m through point (h, k)
__
The two marked points are (-4, 2) and (5, -4). All we need is the slope.
The slope is given by the formula ...
m = (y2 -y1)/(x2 -x1) . . . . . . . . where the given points are (x1, y1) and (x2, y2)
m = (-4 -2)/(5 -(-4)) = -6/9 = -2/3
Using the first point, the equation for the line can now be written as ...
y -2 = -2/3(x -(-4))
y -2 = -2/3(x +4)
